Submission #397052

#TimeUsernameProblemLanguageResultExecution timeMemory
397052khangalLand of the Rainbow Gold (APIO17_rainbow)C++14
0 / 100
24 ms29308 KiB
#include "rainbow.h" #include<bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; using namespace std; typedef long long ll; typedef double db; typedef vector<long long> vl; typedef pair<long long , long long > pl; const int N=1e6+1; #define po pop_back #define pb push_back #define mk make_pair #define lw lower_bound #define up upper_bound #define ff first #define ss second #define boost ios_base::sync_with_stdio(); cin.tie(0); cout.tie(0); #define MOD 1000000007 #define MAX 1e18 #define MIN -1e18 #define rep(i,a,b) for(ll i=a;i<=b;i++) #define per(i,a,b) for(ll i=b;i>=a;i--) #define con continue #define freopen freopen("input.txt", "r", stdin);freopen("output.txt", "w", stdout); #define PI 3.14159265358979323846264338327950288419716939937510582097494459230781640628 // typedef tree<ll , null_type, less<ll>, rb_tree_tag, tree_order_statistics_node_update> indexed_set; // template< typename T> // using indexed_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; ll sz,n,m,ans,mid,mn,mx,cnt,T,sum,h1,h2,e[1234567],b[1234567],c[1234567],d[1<<20],k,i,j,l,r,h,a[1234567],w,x,y,z; bool used[1234567]; vector<ll> v[1234567]; ll dx[4]={-1,1,0,0},dy[4]={0,0,-1,1},c1[123][123]; void init(int R, int C, int sr, int sc, int M, char *S) { string s; n=R;m=C; s=S; x = sr; y = sc; c1[x][y]=1; for(auto u:s){ if(u=='N'){ x--; } if(u=='S'){ x++; } if(u=='W'){ y--; } if(u=='E'){ y++; } c1[x][y]=MAX; } } int colour(int ar,int ac,int br,int bc){ ll a,b,aa,bb,x,y,xx,yy; a = ar; b = ac; aa = br; bb = bc; x = max(a,aa); xx = min(a,bb); y = max(b,bb); yy = min(b,bb); rep(i,xx,x){ rep(j,yy,y){ if(c1[i][j]!=MAX)c1[i][j]=0; } } ans=0; rep(i,xx,x){ rep(j,yy,y){ if(c1[i][j]==0){ ans++; queue<pl> q; q.push({i,j}); while(q.size()){ pl p=q.front(); ll a,b; a=p.ff; b=p.ss; c1[a][b]=1; q.pop(); rep(k,0,3){ if(a+dx[k] <= x && a+dx[k] >= xx &&b+dy[k] <= y && b+dy[k] >= yy && c1[a+dx[k]][b+dy[k]]==0)q.push({a+dx[k] , b+dy[k]}); } } } } } return ans; }
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