Submission #395765

#TimeUsernameProblemLanguageResultExecution timeMemory
395765abdzagPalindromes (APIO14_palindrome)C++17
23 / 100
15 ms1752 KiB
#include<bits/stdc++.h> #define rep(i,a,b) for(int i=int(a);i<int(b);i++) #define rrep(i,a,b) for(int i=int(a);i>int(b); i--); #define all(v) v.begin(),v.end() #define trav(a,v) for(auto&a:v) using namespace std; typedef long long ll; #define MAXN 1000 string s; const ll inf = 1e15; struct Node { // store start and end indexes of current // Node inclusively int start, end; // stores length of substring int length; // stores insertion Node for all characters a-z int insertEdg[26]; // stores the Maximum Palindromic Suffix Node for // the current Node int suffixEdg; int count; }; // two special dummy Nodes as explained above Node root1, root2; // stores Node information for constant time access Node tree[MAXN]; // Keeps track the current Node while insertion int currNode; int ptr; map<string, ll> mp; void insert(int idx) { //STEP 1// /* search for Node X such that s[idx] X S[idx] is maximum palindrome ending at position idx iterate down the suffix link of currNode to find X */ int tmp = currNode; while (true) { int curLength = tree[tmp].length; if (idx - curLength >= 1 and s[idx] == s[idx - curLength - 1]) break; tmp = tree[tmp].suffixEdg; } /* Now we have found X .... * X = string at Node tmp * Check : if s[idx] X s[idx] already exists or not*/ if (tree[tmp].insertEdg[s[idx] - 'a'] != 0) { // s[idx] X s[idx] already exists in the tree currNode = tree[tmp].insertEdg[s[idx] - 'a']; string curs = ""; mp[curs]++; return; } // creating new Node ptr++; // making new Node as child of X with // weight as s[idx] tree[tmp].insertEdg[s[idx] - 'a'] = ptr; // calculating length of new Node tree[ptr].length = tree[tmp].length + 2; // updating end point for new Node tree[ptr].end = idx; // updating the start for new Node tree[ptr].start = idx - tree[ptr].length + 1; string curs = ""; mp[curs]++; //STEP 2// /* Setting the suffix edge for the newly created Node tree[ptr]. Finding some String Y such that s[idx] + Y + s[idx] is longest possible palindromic suffix for newly created Node.*/ tmp = tree[tmp].suffixEdg; // making new Node as current Node currNode = ptr; if (tree[currNode].length == 1) { // if new palindrome's length is 1 // making its suffix link to be null string tree[currNode].suffixEdg = 2; return; } while (true) { int curLength = tree[tmp].length; if (idx - curLength >= 1 and s[idx] == s[idx - curLength - 1]) break; tmp = tree[tmp].suffixEdg; } // Now we have found string Y // linking current Nodes suffix link with s[idx]+Y+s[idx] tree[currNode].suffixEdg = tree[tmp].insertEdg[s[idx] - 'a']; } vector<ll> pi(const string& s) { vector<ll> p(s.size()); rep(i, 1, s.size()) { int g = p[i - 1]; while (g && s[i] != s[g]) g = p[g - 1]; p[i] = g + (s[i] == s[g]); } return p; } ll match(const string& s, const string& pat) { vector<ll> p = pi(pat + '\0' + s); ll res=0; rep(i, p.size() - s.size(), p.size()) if (p[i] == pat.size()) res++; return res; } int main() { cin.sync_with_stdio(false); root1.length = -1; root1.suffixEdg = 1; root2.length = 0; root2.suffixEdg = 1; tree[1] = root1; tree[2] = root2; ptr = 2; currNode = 1; cin >> s; int l = s.size(); rep(i, 0, l) insert(i); ll ans = 0; rep(i, 2, ptr + 1) { string curs = ""; rep(j, tree[i].start, tree[i].end + 1) curs += s[j]; ll val = match(s, curs)*curs.size(); ans=max(ans,val); } cout << ans << endl; return 0; }

Compilation message (stderr)

palindrome.cpp: In function 'll match(const string&, const string&)':
palindrome.cpp:134:18: warning: comparison of integer expressions of different signedness: '__gnu_cxx::__alloc_traits<std::allocator<long long int>, long long int>::value_type' {aka 'long long int'} and 'std::__cxx11::basic_string<char>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
  134 |         if (p[i] == pat.size()) res++;
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