Submission #393957

#TimeUsernameProblemLanguageResultExecution timeMemory
393957Return_0Chase (CEOI17_chase)C++17
100 / 100
283 ms158980 KiB
#pragma GCC optimize("Ofast,unroll-loops") // #pragma comment(linker, "/stack:200000000") // #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,fma,tune=native") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef pair <ll, ll> pll; #ifdef SINA #define dbg(...) __f(#__VA_ARGS__, __VA_ARGS__) template <typename Arg1> void __f(const char* name, Arg1&& arg1) { cout << name << " : " << arg1 << std::endl; } template <typename Arg1, typename... Args> void __f (const char* names, Arg1&& arg1, Args&&... args) { const char* comma = strchr(names + 1, ',');cout.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...); } #define dbg2(x, j, n) cout<< #x << " : "; output((j), (n), x, 1); cout.flush(); #else #define dbg(...) 0 #define dbg2(x, j, n) 0 #endif #define SZ(x) ((ll)((x).size())) #define File(s, t) freopen(s ".txt", "r", stdin); freopen(t ".txt", "w", stdout); #define input(j, n, a) for (int _i = (j); _i < (n)+(j); _i++) cin>> a[_i]; #define output(j, n, a, t) for (int _i = (j); _i < (n)+(j); _i++) cout<< a[_i] << (((t) && _i != (n)+(j)-1)? ' ' : '\n'); #define kill(x) return cout<< (x) << endl, 0 #define cl const ll #define fr first #define sc second #define lc (v << 1) #define rc (lc | 1) #define mid ((l + r) >> 1) #define All(x) (x).begin(), (x).end() cl inf = sizeof(ll) == 4 ? (1e9 + 10) : (3e18), mod = 1e9 + 7, MOD = 998244353; template <class A,class B> ostream& operator << (ostream& out,const pair<A,B>&a){return out<<'('<<a.first<<", "<<a.second<<')';} template <class A> ostream& operator << (ostream& out, const vector<A> &a) { out<< '['; for (int i = -1; ++i < int(a.size());) out<< a[i] << (i + 1 < int(a.size()) ? ", " : ""); return out<<']'; } template <class T, typename _t = less <T> > using Tree = tree <T, null_type, _t, rb_tree_tag, tree_order_statistics_node_update>; cl N = 1e5 + 3, K = 1e2 + 3; ll val [N], dp1 [N][K], dp2 [N][K], ans; int a [N], n, k; vector <int> adj [N]; void dfs (const int &v = 1, const int pr = 0) { dp1[v][1] = val[v]; for (auto &u : adj[v]) if (u != pr) { dfs(u, v); ll pd1, pd2; for (int i = 1; i < k; i++) { pd1 = max(dp1[u][i], dp1[u][i - 1] + val[v] - a[u]), pd2 = max(dp2[u][i], dp2[u][i - 1] + val[u] - a[v]); ans = max(ans, max(dp1[v][k - i] + pd2, dp2[v][k - i] + pd1)); ans = max(ans, dp2[u][i] + val[v]); } for (int i = 1; i <= k; i++) { pd1 = max(dp1[u][i], dp1[u][i - 1] + val[v] - a[u]), pd2 = max(dp2[u][i], dp2[u][i - 1] + val[u] - a[v]); dp1[v][i] = max(dp1[v][i], pd1); dp2[v][i] = max(dp2[v][i], pd2); ans = max(ans, dp1[v][i]); } } } int main () { ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); cin>> n >> k; input(1, n, a); for (int i = 1, v, u; i < n; i++) { cin>> v >> u; adj[v].push_back(u); adj[u].push_back(v); val[v] += a[u]; val[u] += a[v]; } if (!k) kill(0); ans = *max_element(val, val + N); dfs(); cout<< ans << endl; cerr<< "\nTime elapsed: " << 1000 * clock() / CLOCKS_PER_SEC << "ms\n"; return 0; } /* 12 3 2 3 3 8 1 5 6 7 8 3 5 4 2 1 2 7 3 4 4 7 7 6 5 6 6 8 6 9 7 10 10 11 10 12 */
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