이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include "advisor.h"
#define S second
using namespace std;
void appendint(int x,int len){
//printf("%d\n",x);
for(int i=0;i<=len;i++)
WriteAdvice(char((1<<i)&x>0));
}
const int N1 = 2e5+100;
int nxt[N1],last[N1];
vector<int>freq[N1];
map<int,int>pos;
void ComputeAdvice(int *C, int N, int K, int M) {
int len = 0;
for(int i=1;;i++){
if((1<<i)>K)break;
len = i;
}
int n = N;
for(int i=0;i<n;i++)
freq[C[i]].push_back(i);
for(int i=0;i<n;i++)
freq[i].push_back(n+100);
set<pair<int,int>>st;
set<int>st1;
for(int i=0;i<K;i++)
st.insert({freq[i][0],i}),st1.insert(i),pos[i] = i;
for(int i=0;i<n;i++){
if(st1.find(C[i])!=st1.end()){
appendint(0,len);
st.erase({i,C[i]});
int nxt = upper_bound(freq[C[i]].begin(),freq[C[i]].end(),i)-freq[C[i]].begin();
nxt = freq[C[i]][nxt];
st.insert({nxt,C[i]});
}
else {
auto it = st.rbegin();
int val = (*it).S;
st1.erase(val);
st1.insert(C[i]);
pos[C[i]] = pos[val];
appendint(pos[val]+1,len);
st.erase(*it);
int nxt = upper_bound(freq[C[i]].begin(),freq[C[i]].end(),i)-freq[C[i]].begin();
nxt = freq[C[i]][nxt];
st.insert({nxt,C[i]});
}
}
}
#include <bits/stdc++.h>
#include "assistant.h"
using namespace std;
int a[2000000],vals[2000000];
int get(int idx,int len){
int ret = 0;
for(int i=idx;i<=idx+len;i++)
ret += (1<<(i-idx))*a[i];
return ret;
}
void Assist(unsigned char *A, int N, int K, int R) {
// printf("%d\n",R);
// for(int i=0;i<R;i++)
// cout<<A[i];
int len = 0;
for(int i=0;;i++){
if((1<<i)>K)break;
len = i;
}
for(int i=0;i<K;i++)
vals[i] = i;
for(int i=0;i<R;i++)
a[i] = A[i];
int n = N;
for(int i=0;i<n;i++){
int val = GetRequest();
int val1 = get(i*(len+1),len);
if(!val1)continue;
PutBack(vals[val1-1]);
vals[val1-1] = val;
}
}
컴파일 시 표준 에러 (stderr) 메시지
advisor.cpp: In function 'void appendint(int, int)':
advisor.cpp:11:28: warning: suggest parentheses around comparison in operand of '&' [-Wparentheses]
11 | WriteAdvice(char((1<<i)&x>0));
| ~^~
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