This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
template <class T>
using Vec = std::vector<T>;
using ll = long long;
constexpr ll sq(const ll x) {
return x * x;
}
int main() {
int N;
std::cin >> N;
Vec<ll> X(N), Y(N), R(N);
for (int i = 0; i < N; ++i) {
std::cin >> X[i] >> Y[i] >> R[i];
}
Vec<int> order(N);
std::iota(order.begin(), order.end(), 0);
std::stable_sort(order.begin(), order.end(), [&](const int i, const int j) {
return R[i] > R[j];
});
Vec<int> ans(N, -1);
if (N <= 5000) {
for (const auto x: order) {
if (ans[x] == -1) {
ans[x] = x;
for (int i = 0; i < N; ++i) {
if (ans[i] == -1 and sq(X[i] - X[x]) + sq(Y[i] - Y[x]) <= sq(R[i] + R[x])) {
ans[i] = x;
}
}
}
}
}
else {
std::set<std::pair<ll, int>> set;
for (int i = 0; i < N; ++i) {
set.emplace(X[i] - R[i], i);
set.emplace(X[i] + R[i], i);
}
for (const auto x: order) {
if (ans[x] == -1) {
ans[x] = x;
while (true) {
auto itr = set.lower_bound(std::make_pair(X[x] - R[x], 0));
if (itr == set.end() or itr -> first > X[x] + R[x]) {
break;
}
const auto i = itr -> second;
ans[i] = x;
set.erase(std::make_pair(X[i] - R[i], i));
set.erase(std::make_pair(X[i] + R[i], i));
}
}
}
}
for (int i = 0; i < N; ++i) {
std::cout << ans[i] + 1 << " \n"[i + 1 == N];
}
}
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