Submission #389077

#	Time	Username	Problem	Language	Result	Execution time	Memory
389077		arwaeystoamneg	Hiring (IOI09_hiring)	C++17	5 / 100	907 ms	44996 KiB

hiring

// EXPLOSION!
#define _CRT_SECURE_NO_WARNINGS
#include<bits/stdc++.h>
#include<unordered_set>
#include<unordered_map>
#include<chrono>

using namespace std;
typedef pair<int, int> pii;
typedef long long ll;
typedef pair<ll, ll> pll;
typedef long double ld;
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<pair<int, int>> vpi;
typedef vector<pair<ll, ll>> vpll;

#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define F0R(i,a) FOR(i,0,a)
#define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i)
#define R0F(i,a) ROF(i,0,a)
#define trav(a,x) for (auto& a: x)

#define pb push_back
#define mp make_pair
#define rsz resize
#define sz(x) int(x.size())
#define all(x) x.begin(),x.end()
#define f first
#define s second
#define cont continue
#define endl '\n'
//#define ednl '\n'
#define test int testc;cin>>testc;while(testc--)
#define pr(a, b) trav(x,a)cerr << x << b; cerr << endl;
#define message cout << "Hello World" << endl;
const int dx[4] = { 1,0,-1,0 }, dy[4] = { 0,1,0,-1 }; // for every grid problem!!
const ll linf = 4000000000000000000LL;
const ll inf = 1000000007;//998244353  
const ld pi = 3.1415926535;

void pv(vi a) { trav(x, a)cout << x << " "; cout << endl; }void pv(vll a) { trav(x, a)cout << x << " "; cout << endl; }void pv(vector<vi>a) {
	F0R(i, sz(a)) { cout << i << endl; pv(a[i]); cout << endl; }
}void pv(vector<vll>a) { F0R(i, sz(a)) { cout << i << endl; pv(a[i]); }cout << endl; }void pv(vector<string>a) { trav(x, a)cout << x << endl; cout << endl; }
void setIO(string s) {
	ios_base::sync_with_stdio(0); cin.tie(0);
	if (sz(s))
	{
		freopen((s + ".in").c_str(), "r", stdin);
		if (s != "test1")
			freopen((s + ".out").c_str(), "w", stdout);
	}
}
template<class T>class segment_tree
{
	struct item
	{
		T sum;
	};
	item single(T i)
	{
		return { i };
	}
	item merge(item x, item y)
	{
		item ans;
		ans.sum = x.sum + y.sum;
		return ans;
	}
	vector<item> tree;
	vector<item>A;
	int height;
	item neutral = { 0 };
public:void build(vector<T>& B)
{
	int	n = B.size();
	height = log2(n + 1) + 1;
	A.rsz(n);
	tree.rsz((1 << height + 1) - 1);
	F0R(i, n)A[i] = single(B[i]);
	A.rsz(1 << height, neutral);
	build(A, 0, 0, (1 << height) - 1);
}
	  void build(vector<item>& A, int v, int tl, int tr)
	  {
		  if (tl == tr)
			  tree[v] = A[tl];
		  else
		  {
			  int mid = (tl + tr) / 2;
			  build(A, 2 * v + 1, tl, mid);
			  build(A, 2 * v + 2, mid + 1, tr);
			  tree[v] = merge(tree[2 * v + 1], tree[2 * v + 2]);
		  }
	  }
public:T query(int l, int r)
{
	return query(0, 0, (1 << height) - 1, l, r).sum;
}
	  item query(int v, int tl, int tr, int l, int r)
	  {
		  if (r<tl || l>tr)return neutral;
		  if (l <= tl && r >= tr)
		  {
			  return tree[v];
		  }
		  int mid = (tl + tr) / 2;
		  return merge(query(2 * v + 1, tl, mid, l, r), query(2 * v + 2, mid + 1, tr, l, r));
	  }
	  //assign
public:void update(int pos, T val)
{
	update(0, 0, (1 << height) - 1, pos, single(val));
}
	  void update(int v, int tl, int tr, int pos, item val)
	  {
		  if (tl == tr)
		  {
			  tree[v] = val;
		  }
		  else
		  {
			  int mid = (tl + tr) / 2;
			  if (pos <= mid)
				  update(2 * v + 1, tl, mid, pos, val);
			  else
				  update(2 * v + 2, mid + 1, tr, pos, val);
			  tree[v] = merge(tree[2 * v + 1], tree[2 * v + 2]);
		  }
	  }
public:int get(T k)
{
	return get(0, 0, (1 << height) - 1, k);
}
	  int get(int v, int tl, int tr, T k)
	  {
		  if (tl == tr)return tl;
		  int mid = (tl + tr) / 2;
		  if (k >= tree[2 * v + 1].sum)
			  return get(2 * v + 2, mid + 1, tr, k - tree[2 * v + 1].sum);
		  return get(2 * v + 1, tl, mid, k);
	  }
};

int n;
const int MAX = 5e5 + 5;
ll w;
int a[MAX], b[MAX], order[MAX], order1[MAX];
int main()
{
	setIO("");
	cin >> n >> w;
	F0R(i, n)cin >> a[i] >> b[i];
	iota(order, order + n, 0);
	sort(order, order + n, [](int i, int j) {return a[j] * b[i] < a[i] * b[j]; });
	iota(order1, order1 + n, 0);
	sort(order1, order1 + n, [](int i, int j) {return b[i] < b[j]; });
	vi temp(n, 1);
	segment_tree<int>active;
	active.build(temp);
	vll temp1(n);
	F0R(i, n)temp1[i] = b[order1[i]];
	segment_tree<ll>cost;
	cost.build(temp1);
	pii ans = { -inf,-1 };
	F0R(i, n)
	{
		active.update(order1[order[i]], 0);
		cost.update(order1[order[i]], 0);
		int p = cost.get((w - a[order[i]]) * b[order[i]] / a[order[i]]);
		ans = max(ans, { (p == 0 ? -1 : active.query(0, p - 1)) + 1,i });
	}
	cout << ans.f << endl;
	if (ans.f == 0)
	{
		return 0;
	}
//	F0R(i, ans.f)cout << i + 1 << endl;
//	return 0;
	//cout << ans.second << endl;
	int i = ans.s;
	vector<int>x = { order[i] };
	w -= a[order[i]];
	w *= b[order[i]];
	w /= a[order[i]];
	vpi todo;
	FOR(j, i + 1, n)
	{
		todo.pb({ b[order[j]],order[j] });
	}
	sort(all(todo));
	trav(t, todo)
	{
		if (w >= t.f)
		{
			w -= t.f;
			x.pb(t.s);
		}
	}
	trav(y, x)cout << y + 1 << endl;
}

Compilation message (stderr)

hiring.cpp: In instantiation of 'void segment_tree<T>::build(std::vector<_Tp>&) [with T = int]':
hiring.cpp:160:19:   required from here
hiring.cpp:79:24: warning: suggest parentheses around '+' inside '<<' [-Wparentheses]
   79 |  tree.rsz((1 << height + 1) - 1);
      |                 ~~~~~~~^~~
hiring.cpp: In instantiation of 'void segment_tree<T>::build(std::vector<_Tp>&) [with T = long long int]':
hiring.cpp:164:18:   required from here
hiring.cpp:79:24: warning: suggest parentheses around '+' inside '<<' [-Wparentheses]
hiring.cpp: In function 'void setIO(std::string)':
hiring.cpp:49:10: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
   49 |   freopen((s + ".in").c_str(), "r", stdin);
      |   ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
hiring.cpp:51:11: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
   51 |    freopen((s + ".out").c_str(), "w", stdout);
      |    ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 5 / 30
• Subtask 2: 0 / 28
• Subtask 3: 0 / 6
• Subtask 4: 0 / 6
• Subtask 5: 0 / 6
• Subtask 6: 0 / 6
• Subtask 7: 0 / 6
• Subtask 8: 0 / 6
• Subtask 9: 0 / 6