This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "supertrees.h"
#include <vector>
#include <numeric>
using namespace std;
const int MAXN = 1e3;
int pa[MAXN];
int ra[MAXN];
void init() {
    iota(pa, pa + MAXN, 0);
    fill(ra, ra + MAXN, 0);
}
int get(int a) {
    if (a == pa[a])
        return a;
    return pa[a] = get(pa[a]);
}
void merge(int a, int b) {
    a = get(a);
    b = get(b);
    if (a == b)
        return;
    if (ra[b] > ra[a])
        swap(a, b);
    pa[b] = a;
    if (ra[a] == ra[b])
        ra[a]++;
}
vector<vector<int>> g;
vector<vector<int>> p2;
vector<int> comp;
vector<int> used;
int cur_time = 1;
void dfs(int v) {
    used[v] = cur_time;
    comp.push_back(v);
    for (int u : g[v]) {
        if (used[u] < cur_time) {
            dfs(u);
        }
    }
}
int construct(vector<vector<int>> p) {
    init();
    int n = p.size();
    used.resize(n);
    g.resize(n);
    p2.resize(n, vector<int> (n));
    vector<vector<int>> answer;
    for (int i = 0; i < n; i++) {
        vector<int> row;
        row.resize(n);
        answer.push_back(row);
    }
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            if (p[i][j] == 3)
                return 0;
        }
    }
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            if (p[i][j] == 1) {
                if (get(i) != get(j)) {
                    merge(i, j);
                    comp.clear();
                    dfs(i);
                    cur_time++;
                    auto c1 = comp;
                    comp.clear();
                    dfs(j);
                    cur_time++;
                    auto c2 = comp;
                    for (int el1 : c1) {
                        for (int el2 : c2) {
                            p2[el2][el1] = 1;
                            p2[el1][el2] = 1;
                        }
                    }
                    g[i].push_back(j);
                    g[j].push_back(i);
                    answer[i][j] = 1;
                    answer[j][i] = 1;
                }
            }
        }
    }
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            if (p[i][j] == 2) {
            }
        }
    }
    for (int i = 0; i < n; i++) {
        p2[i][i] = 1;
    }
    if (p != p2) {
        return 0;
    }
    build(answer);
    return 1;
}
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