#include <iostream>
#include <string>
#include <math.h>
#include <algorithm>
#include <vector>
#include <string.h>
#include <numeric>
#include <iostream>
#include <queue>
#include <assert.h>
#include <map>
#include <set>
#include <limits.h>
#include <random>
#include <chrono>
using namespace std;
#define ll long long
#define ld long double
const int MX = 200005;
const int BLOCK = 105;
const ll mod = 1e9 + 7;
const ll inv2 = (mod + 1) / 2;
const int dxh[] = {1, 1, -1, -1, 2, 2, -2, -2};
const int dyh[] = {2, -2, 2, -2, 1, -1, 1, -1}; // horse
const int dx[] = {1, -1, 0, 0, 0, 0};
const int dy[] = {0, 0, 1, -1, 0, 0}; // adj
const int dz[] = {0, 0, 0, 0, 1, -1};
const int dxd[] = {1, 1, 1, 0, -1, -1, -1, 0};
const int dyd[] = {1, 0, -1, -1, -1, 0, 1, 1}; // diag
int n, m, k, q, queries_used = 0;
vector<vector<vector<int> > > v;
int ask(int x, int y, int z){
if(x < 1 || x > n || y < 1 || y > m || z < 1 || z > k)
return -1;
if(v[x - 1][y - 1][z - 1] != 0)
return v[x - 1][y - 1][z - 1];
cout << "? " << x << " " << y << " " << z << endl;
int rs; cin >> rs;
v[x - 1][y - 1][z - 1] = rs;
return rs;
}
void answer(int x, int y, int z){
cout << "! " << x << " " << y << " " << z << endl;
exit(0);
}
bool ok(int x, int y, int z){
vector<int> aa;
aa.push_back(ask(x, y, z));
for(int d = 0; d < 6; d ++)
aa.push_back(ask(x + dx[d], y + dy[d], z + dz[d]));
sort(aa.begin(), aa.end());
if(aa.back() == ask(x, y, z)) return true;
return false;
}
mt19937 rng(time(NULL));
int main(){
cin >> n >> m >> k;
v.assign(n, vector<vector<int> >(m, vector<int>(k, 0)));
cin >> q;
if(m == k && k == 1){
int lf = 1, rg = n;
for(int md; lf < rg;){
md = (lf + rg) / 2;
if(ask(md, 1, 1) > ask(md + 1, 1, 1))
rg = md;
else
lf = md + 1;
}
answer(lf, 1, 1);
}
int mx = -1, xx, yy, zz;
for(int x, y, z; queries_used < q / 2; queries_used ++){
x = rng() % n + 1;
y = rng() % m + 1;
z = rng() % k + 1;
if(mx < ask(x, y, z)){
mx = ask(x, y, z);
xx = x, yy = y, zz = z;
}
}
while(!ok(xx, yy, zz)){
for(int d = 0; d < 6; d ++){
int nx = xx + dx[d], ny = yy + dy[d], nz = zz + dz[d];
if(ask(nx, ny, nz) > ask(xx, yy, zz)){
xx = nx, yy = ny, zz = nz;
break;
}
}
}
answer(xx, yy, zz);
return 0;
}
