Submission #384512

#	Time	Username	Problem	Language	Result	Execution time	Memory
384512		couplefire	Džumbus (COCI19_dzumbus)	C++17	110 / 110	509 ms	24392 KiB

dzumbus

#include <bits/stdc++.h>
using namespace std;
#define MAXN 1005
#define INF 1061109567

int ckmin(int &a, int b){return (b<a)?a=b:a;}
int ckmax(int &a, int b){return (b>a)?a=b:b;}

int n, m, q;
int arr[MAXN];
vector<int> adj[MAXN];
int dp[MAXN][MAXN][3]; //0: no root, 1: yes root but not engaged, 2: yes root and engaged
bool visited[MAXN];
vector<pair<int, int>> ans;

void findcomp(int v, int p){
    visited[v] = 1;
    for(auto u : adj[v]){
        if(u == p) continue;
        findcomp(u, v);
    }
}

int dfs(int v, int p){
    dp[v][0][0] = 0;
    dp[v][0][1] = arr[v];
    int cursiz = 1;
    for(auto u : adj[v]){
        if(u == p) continue;
        int siz = dfs(u, v);
        int tmp[MAXN][3]; memset(tmp, 63, sizeof tmp);
        for(int i = 0; i<=cursiz; i++){
            for(int j = 0; j<=siz; j++){
                ckmin(tmp[i+j][0], dp[v][i][0]+min({dp[u][j][0], dp[u][j][1], dp[u][j][2]}));
                ckmin(tmp[i+j][1], dp[v][i][1]+dp[u][j][0]);
                ckmin(tmp[i+j][2], dp[v][i][2]+min(dp[u][j][0], dp[u][j][2]));
                ckmin(tmp[i+j+1][2], dp[v][i][2]+dp[u][j][1]);
                ckmin(tmp[i+j+1][2], dp[v][i][1]+dp[u][j][2]);
                ckmin(tmp[i+j+2][2], dp[v][i][1]+dp[u][j][1]);
            }
        }
        for(int i = 0; i<MAXN; i++) dp[v][i][0] = tmp[i][0], dp[v][i][1] = tmp[i][1], dp[v][i][2] = tmp[i][2];
        cursiz += siz;
    }
    return cursiz;
}

signed main(){
    // freopen("a.in", "r", stdin);
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cin >> n >> m;
    for(int i = 1; i<=n; i++) cin >> arr[i];
    arr[0] = INF;
    for(int i = 0; i<m; i++){
        int a, b; cin >> a >> b;
        adj[a].push_back(b);
        adj[b].push_back(a);
    }
    for(int i = 1; i<=n; i++){
        if(!visited[i]){
            findcomp(i, 0);
            adj[0].push_back(i);
            adj[i].push_back(0);
        }
    }
    memset(dp, 0x3f, sizeof dp);
    dfs(0, -1);
    for(int i = 0; i<MAXN; i++){
        while(!ans.empty() && dp[0][i][0] <= ans.back().first) ans.pop_back();
        ans.push_back({dp[0][i][0], i});
    }
    cin >> q;
    while(q--){
        int s; cin >> s;
        cout << (*prev(upper_bound(ans.begin(), ans.end(), make_pair(s, MAXN+5)))).second << endl;
    }
}

• Subtask 1: 20 / 20
• Subtask 2: 30 / 30
• Subtask 3: 30 / 30
• Subtask 4: 30 / 30