Submission #383853

#TimeUsernameProblemLanguageResultExecution timeMemory
383853JerryLiu06Secret (JOI14_secret)C++11
0 / 100
505 ms4464 KiB
#include <bits/stdc++.h> #include "secret.h" using namespace std; int dat[10][1010], mask[1010], A[1010]; void divide(int L, int R, int lev, int A[]) { if (L == R) return ; int mid = (L + R) / 2; dat[lev][mid] = A[mid]; for (int i = mid - 1; i >= L; i--) dat[lev][i] = Secret(A[i], dat[lev][i + 1]); dat[lev][mid + 1] = A[mid + 1]; for (int i = mid + 2; i <= R; i++) dat[lev][i] = Secret(A[i], dat[lev][i - 1]); for (int i = mid + 1; i <= R; i++) mask[i] ^= (1 << lev); divide(L, mid, lev + 1, A); divide(mid + 1, R, lev + 1, A); } void Init(int N, int arr[]) { for (int i = 0; i < N; i++) A[i] = arr[i]; divide(0, N - 1, 0, A); } int Query(int L, int R) { if (L == R) return A[L]; int lev = __builtin_ctz(mask[L] ^ mask[R]); return Secret(dat[lev][L], dat[lev][R]); }

Compilation message (stderr)

secret.cpp: In function 'void divide(int, int, int, int*)':
secret.cpp:9:5: warning: this 'if' clause does not guard... [-Wmisleading-indentation]
    9 |     if (L == R) return ; int mid = (L + R) / 2;
      |     ^~
secret.cpp:9:26: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'if'
    9 |     if (L == R) return ; int mid = (L + R) / 2;
      |                          ^~~
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