Submission #383358

#	Time	Username	Problem	Language	Result	Execution time	Memory
383358		tjrwodnjs999	Jakarta Skyscrapers (APIO15_skyscraper)	C++11	10 / 100	3 ms	2028 KiB

skyscraper

#include <bits/stdc++.h>
#define ll long long
#define x first
#define y second
using namespace std;
int n,m,B[30005],P[30005];
ll dist[30005];
vector<int> Map[30005],adj[30005],vt[10][10];
priority_queue<pair<ll,int>> pq;
int main()
{
    scanf("%d%d",&n,&m);
    for(int i=1;i<=m;i++){
        scanf("%d%d",&B[i],&P[i]);
        Map[B[i]].push_back(i);
        for(int j=1;j<10;j++) vt[j][B[i]%j].push_back(i);
    }
    for(int i=1;i<=m;i++){
        if(P[i]>=10){
            for(int j:Map[B[i]]) if(j!=i) adj[i].push_back(j);
            for(int j=B[i]+P[i];j<n;j++){
                for(int k:Map[j]) adj[i].push_back(k);
            }
            for(int j=B[i]-P[i];j>=0;j--){
                for(int k:Map[j]) adj[i].push_back(k);
            }
        }
    }
    fill(dist,dist+30005,1e9);
    dist[1]=0; pq.push({0,1});
    while(!pq.empty()){
        int now=pq.top().second;
        ll cost=-pq.top().first; pq.pop();
        if(dist[now]<cost) continue;
        if(P[now]>=10){
            for(int i:adj[now]){
                ll d=abs(B[i]-B[now])/P[now];
                if(dist[i]>cost+d) dist[i]=cost+d,pq.push({-dist[i],i});
            }
        }
        else{
            for(int i:vt[P[now]][B[now]%P[now]]){
                ll d=abs(B[i]-B[now])/P[now];
                if(dist[i]>cost+d) dist[i]=cost+d,pq.push({-dist[i],i});
            }
        }
    }
    printf("%lld",dist[2]==1e9?-1:dist[2]);
    return 0;
}

Compilation message (stderr)

skyscraper.cpp: In function 'int main()':
skyscraper.cpp:12:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   12 |     scanf("%d%d",&n,&m);
      |     ~~~~~^~~~~~~~~~~~~~
skyscraper.cpp:14:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   14 |         scanf("%d%d",&B[i],&P[i]);
      |         ~~~~~^~~~~~~~~~~~~~~~~~~~

• Subtask 1: 10 / 10
• Subtask 2: 0 / 12
• Subtask 3: 0 / 14
• Subtask 4: 0 / 21
• Subtask 5: 0 / 43