Submission #381369

#	Time	Username	Problem	Language	Result	Execution time	Memory
381369		Vimmer	Zagrade (COI20_zagrade)	C++14	0 / 100	3071 ms	1388 KiB

zagrade

#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>

//#pragma GCC optimize("-O3")
//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("-Ofast")

#define N 100500
#define NN 1005000
#define PB push_back
//#define endl '\n'
#define pri(x) cout << x << endl
#define _ << " " <<
#define all(x) x.begin(), x.end()
#define sz(x) int(x.size())
#define M ll(1e9 + 7)
#define F first
#define S second

using namespace std;
//using namespace __gnu_pbds;

typedef long long ll;
typedef long double ld;
typedef short int si;
typedef unsigned long long ull;

//typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;

//ordered_set se;

void TL()
{
    while (1)
    {

    }
}

int nx[N], ls[N], n, q;

int ask(int l, int r)
{
    q--;

    if (q == -1)
        TL();

    pri("?" _ l _ r);

    int x;

    cin >> x;

    return x;
}


char ans[N];

int main()
{
    ios_base::sync_with_stdio(0); istream::sync_with_stdio(0); cin.tie(0); cout.tie(0);

    //freopen("1.in", "r", stdin);

    cin >> n >> q;

    for (int i = 2; i <= n; i++)
        ls[i] = i - 1;

    nx[n] = ls[1] = -1;

    for (int i = 1; i < n; i++)
        nx[i] = i + 1;

    for (int i = 1; i <= n; i++)
        ans[i] = 'a';

    int kl = n, beg = 1;

    while (kl)
    {
        while (ans[beg] != 'a')
            beg++;

        int cur = beg;

        while (cur != -1)
        {
            int l = cur, r = nx[cur];

            if (r == -1)
                break;

            if (l < 1 || n < l)
                TL();

            if (r < 1 || n < r)
                TL();

            if (ans[l] == 'a' && ans[r] == 'a' && ask(l, r))
            {
                ans[l] = '(';

                ans[r] = ')';

                int lst = ls[l];

                int nxt = nx[r];

                if (lst != -1)
                    nx[lst] = nxt;

                if (nxt != -1)
                    ls[nxt] = lst;

                cur = nxt;

                kl -= 2;
            }
            else
            cur = r;
        }
    }

    cout << "! ";

    for (int i = 1; i <= n; i++)
        cout << ans[i];

    cout << endl;
}

• Subtask 1: 0 / 14
• Subtask 2: 0 / 7
• Subtask 3: 0 / 57
• Subtask 4: 0 / 22