이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
#define jizz ios_base::sync_with_stdio(false);cin.tie(NULL);
typedef long long ll;
typedef pair<int,int> pii;
#define F first
#define S second
#define ALL(x) (x).begin(),(x).end()
#define pb push_back
#define mkp make_pair
bool cmp(pii a, pii b){
    return a.F+a.S<b.F+b.S;
}
int abs(int x){
    return x>0?x:-x;
}
vector<pii> segs, pos;
map<int,int> ls, lb, rs, rb;
int main(){ jizz
    int k, n;
    cin>>k>>n;
    ll tmp=0;
    for(int i=0;i<n;i++){
        char p, q;
        int s, t;
        cin>>p>>s>>q>>t;
        if(s>t) swap(s,t);
        tmp+=(t-s);
        if(p!=q) {
            tmp++;
            segs.pb(mkp(s,t));
            pos.pb(mkp(s,0));
            pos.pb(mkp(t,1));
        }
    }
    ll ans=tmp;
    if(segs.empty()){
        cout<<tmp<<"\n";
        return 0;
    }
    sort(ALL(segs),cmp);
    sort(ALL(pos));
    int sz=segs.size();
    ll lsum=0, rsum=0;
    for(int i=0;i<sz;i++){
        rs[pos[i].F]++;
        if(pos[i].S==1) rsum-=2*(pos[i].F);
    }
    for(int i=sz;i<sz*2;i++){
        rb[pos[i].F]++;
        if(pos[i].S==0) rsum+=2*(pos[i].F);
    }
    if(k==1){
        cout<<ans+lsum+rsum<<"\n";
        return 0;
    }
    ll ans2=ans+lsum+rsum;
    for(int i=0;i<sz;i++){
        rs[segs[i].F]--;
        if(segs[i].S<rb.begin()->F){
            rs[segs[i].S]--;
            rsum+=2*segs[i].S;
            auto p=rb.begin();
            rsum-=2*(p->F);
            rb[p->F]--;
            rs[p->F]++;
        } else{
            rb[segs[i].S]--;
        }
        lb[segs[i].S]++;
        if(segs[i].F<lb.begin()->F){
            ls[segs[i].F]++;
        } else{
            lb[segs[i].F]++;
            lsum+=2*segs[i].F;
            auto p=lb.begin();
            lsum-=2*(p->F);
            lb[p->F]--;
            ls[p->S]++;
        }
        ans2=min(ans2,ans+lsum+rsum);
    }
    cout<<ans2<<"\n";
    return 0;
}
/*
1 5
B 0 A 4
B 1 B 3
A 5 B 7
B 2 A 6
B 1 A 7
2 5
B 0 A 4
B 1 B 3
A 5 B 7
B 2 A 6
B 1 A 7
2 3
A 3 B 3
A 4 B 4
A 5 B 5
*/
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