Submission #379499

#	Time	Username	Problem	Language	Result	Execution time	Memory
379499		ACmachine	Roads (CEOI20_roads)	C++17	30 / 100	104 ms	10596 KiB

roads

#include <bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;

template<typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<typename T, typename U> using ordered_map = tree<T, U, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

typedef long long ll;
typedef long double ld;

typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

typedef vector<int> vi;
typedef vector<ll> vll;

#define FOR(i,j,k,in) for(int i=(j); i < (k);i+=in)
#define FORD(i,j,k,in) for(int i=(j); i >=(k);i-=in)
#define REP(i,b) FOR(i,0,b,1)
#define REPD(i,b) FORD(i,b,0,1)
#define pb push_back
#define mp make_pair
#define ff first
#define ss second
#define all(x) begin(x), end(x)
#define MANY_TESTS int tcase; cin >> tcase; while(tcase--)

const double EPS = 1e-9;
const int MOD = 1e9+7;
const ll INFF = 1e18;
const int INF = 1e9;
const ld PI = acos((ld)-1);
const vi dy = {1, 0, -1, 0, -1, 1, 1, -1};
const vi dx = {0, 1, 0, -1, -1, 1, -1, 1};

void DBG(){cout << "]" << endl;}
template<typename T, typename ...U> void DBG(const T& head, const U... args){ cout << head << "; "; DBG(args...); }
#define dbg(...) cout << "Line(" << __LINE__ << ") -> [" << #__VA_ARGS__ << "]: [", DBG(__VA_ARGS__);
#define chk() cout << "Check at line(" << __LINE__ << ") hit." << endl;

template<class T, unsigned int U>
ostream& operator<<(ostream& out, const array<T, U> &v){out << "[";  REP(i, U) out << v[i] << ", ";  out << "]"; return out;}
template <class T, class U>
ostream& operator<<(ostream& out, const pair<T, U> &par) {out << "[" << par.first << ";" << par.second << "]"; return out;}
template <class T>
ostream& operator<<(ostream& out, const set<T> &cont) { out << "{"; for( const auto &x:cont) out << x << ", "; out << "}"; return out; }
template <class T, class U>
ostream& operator<<(ostream& out, const map<T, U> &cont) {out << "{"; for( const auto &x:cont) out << x << ", "; out << "}"; return out; }
template<class T>
ostream& operator<<(ostream& out, const vector<T> &v){ out << "[";  REP(i, v.size()) out << v[i] << ", ";  out << "]"; return out;}

template<class T>
istream& operator>>(istream& in, vector<T> &v){ for(auto &x : v) in >> x; return in; }
typedef complex<long long> P;


int main(){
 	ios_base::sync_with_stdio(false);
 	cin.tie(NULL); cout.tie(NULL);
    int n; cin >> n;
    vector<pair<int, pair<int, int>>> lines(n);
    bool vertical = false;
    vector<array<int, 4>> lines2(n);
    REP(i, n){
        int x1, y1, x2, y2;
        cin >> x1 >> y1 >> x2 >> y2;
        if(x1 == x2){
            vertical = true;
        }
        if(vertical){
            if(y1 > y2) swap(y1, y2);
            lines[i].ff = x1;
            lines[i].ss = make_pair(y1, y2);
        }
        else{
            if(x1 > x2){
                swap(x1, x2);
                swap(y1, y2);
            }
            lines2[i] = {x1, y1, x2, y2};
        }
    }

    auto solve_vertical = [&](){
        sort(all(lines));
        vector<array<int, 4>> ans;
        FOR(i, 1, n, 1){
            ans.pb({lines[i].ff, lines[i].ss.ff, lines[i - 1].ff, lines[i - 1].ss.ss});
        }
        REP(i, n - 1){
            REP(j, 4){
                cout << ans[i][j] << (j == 3 ? "\n" : " ");
            }
        }
    };
    auto solve_parallel = [&](){
        auto cross = [&](P a, P b){
            return a.real() * b.imag() - a.imag() * b.real();
        };
        auto comp = [&](array<int, 4> lhs, array<int, 4> rhs){
            P f = {lhs[0], lhs[1]}; P s = {lhs[2], lhs[3]};
            P t = {rhs[0], rhs[1]};
            P v1 = s - f;
            P v2 = t - f;
            if(cross(v1, v2) == 0){
                return lhs[0] < rhs[0];
            }
            else{
                return cross(v1, v2) > 0;
            }
        };
        sort(all(lines2), comp);
        vector<array<int, 4>> ans;
        FOR(i, 1, n , 1){
            ans.pb({lines2[i][0], lines2[i][1], lines2[i - 1][2], lines2[i - 1][3]});
        }
        REP(i, n - 1){
            REP(j, 4){
                cout << ans[i][j] << (j == 3 ? "\n" : " ");
            }
        }
    };
    if(vertical)
        solve_vertical();
    else{
        solve_parallel();
    }
    return 0;
}

• Subtask 1: 0 / 0
• Subtask 2: 15 / 15
• Subtask 3: 15 / 15
• Subtask 4: 0 / 15
• Subtask 5: 0 / 15
• Subtask 6: 0 / 40