제출 #378228

#제출 시각아이디문제언어결과실행 시간메모리
378228AmineWeslati벽 (IOI14_wall)C++14
0 / 100
34 ms47340 KiB
//Never stop trying #include "bits/stdc++.h" using namespace std; #define boost ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0) typedef long long ll; typedef string str; typedef long double ld; typedef pair<int, int> pi; #define fi first #define se second typedef vector<int> vi; typedef vector<pi> vpi; #define pb push_back #define eb emplace_back #define sz(x) (int)x.size() #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) #define endl "\n" #define FOR(i,a,b) for (int i = (a); i < (b); ++i) #define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i) const int MOD = 1e9 + 7; //998244353 const ll INF = 2e9; const int MX = 2e5 + 10; const int nx[4] = {0, 0, 1, -1}, ny[4] = {1, -1, 0, 0}; //right left down up template<class T> using V = vector<T>; template<class T> bool ckmin(T& a, const T& b) { return a > b ? a = b, 1 : 0; } template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); } // divide a by b rounded up //constexpr int log2(int x) { return 31 - __builtin_clz(x); } // floor(log2(x)) mt19937 rng(chrono::system_clock::now().time_since_epoch().count()); //mt19937_64 rng(chrono::system_clock::now().time_since_epoch().count()); ll random(ll a, ll b){ return a + rng() % (b - a + 1); } #ifndef LOCAL #define cerr if(false) cerr #endif #define dbg(x) cerr << #x << " : " << x << endl; #define dbgs(x,y) cerr << #x << " : " << x << " / " << #y << " : " << y << endl; #define dbgv(v) cerr << #v << " : " << "[ "; for(auto it : v) cerr << it << ' '; cerr << ']' << endl; #define here() cerr << "here" << endl; void IO() { #ifdef LOCAL freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout); #endif } /////////////////////////ONLY CLEAN CODES ALLOWED///////////////////////// const int mxQ=5e5+10,mxN=2e6+10; #ifndef LOCAL #include "wall.h" #endif int N,Q; vpi vec[mxN]; vi t[2]; int combine(int t, int x, int y){ if(t==0) return max(x,y); return min(x,y); } void upd(int n, int idx, int v, int pos=1, int l=0, int r=Q-1){ if(l==r){ t[n][pos]=v; return; } int m=(l+r)/2; if(idx<=m) upd(n,idx,v,pos*2,l,m); else upd(n,idx,v,pos*2+1,m+1,r); t[n][pos]=combine(n,t[n][pos*2],t[n][pos*2+1]); } int get(int n, int l, int r, int pos=1, int tl=0, int tr=Q-1){ if(l>r){ if(n==0) return 0; return INF; } if(l==tl && r==tr){ return t[n][pos]; } int tm=(tl+tr)/2; return combine(n,get(n,l,min(tm,r),pos*2,tl,tm), get(n,max(l,tm+1),r,pos*2+1,tm+1,tr)); } int solve(){ int l=0,r=Q-1,idx=Q; int xx=0; while(l<=r){ int m=(l+r)/2; int x=get(0,m,Q-1); if(x<=get(1,m,Q-1)){ idx=m; r=m-1; xx=x; } else l=m+1; } int ans=xx; //ckmax(ans,get(0,idx,Q-1)); if(idx) ckmax(ans,get(1,idx-1,Q-1)); return ans; } void buildWall(int N, int Q, int op[], int L[], int R[], int H[], int fH[]){ ::N=N; ::Q=Q; t[0].assign(Q*4+10,0); t[1].assign(Q*4+10,INF); FOR(i,0,Q){ int l=L[i],r=R[i]; vec[l].pb({i,1}); vec[r+1].pb({i,-1}); } FOR(i,0,N){ for(auto it: vec[i]){ int idx=it.fi; if(it.se==1){ if(op[idx]==1){ upd(0,idx,H[idx]); } else{ upd(1,idx,H[idx]); } } else{ if(op[idx]==1){ upd(0,idx,0); } else{ upd(1,idx,INF); } } } if(!sz(vec[i])){ if(!i) fH[i]=0; else fH[i]=fH[i-1]; } else fH[i]=solve(); } FOR(i,0,N) cout << fH[i] << ' '; cout << endl; return; } #ifdef LOCAL int main() { boost; IO(); int N,Q; cin>>N>>Q; int op[Q],l[Q],r[Q],h[Q],fH[N]; FOR(i,0,Q) cin>>op[i]>>l[i]>>r[i]>>h[i]; buildWall(N,Q,op,l,r,h,fH); return 0; } #endif //Change your approach

컴파일 시 표준 에러 (stderr) 메시지

wall.cpp: In function 'void buildWall(int, int, int*, int*, int*, int*, int*)':
wall.cpp:20:20: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
   20 | #define FOR(i,a,b) for (int i = (a); i < (b); ++i)
      |                    ^~~
wall.cpp:154:2: note: in expansion of macro 'FOR'
  154 |  FOR(i,0,N) cout << fH[i] << ' '; cout << endl;
      |  ^~~
wall.cpp:154:35: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
  154 |  FOR(i,0,N) cout << fH[i] << ' '; cout << endl;
      |                                   ^~~~
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