Submission #377262

#	TimeUTC-0	Username	Problem	Language	Result	Execution time	Memory
377262	2021-03-13 15:18:15	maomao90	Discharging (NOI20_discharging)	C++14	100 / 100	186 ms	18668 KiB

Discharging

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#include <bits/stdc++.h>
using namespace std;
#define mnto(x, y) x = min(x, (__typeof__(x)) y)
#define mxto(x, y) x = max(x, (__typeof__(x)) y)
#define REP(i, s, e) for (int i = s; i < e; i++)
#define RREP(i, s, e) for (int i = s; i >= e; i--)
typedef long long ll;
typedef long double ld;
#define MP make_pair
#define FI first
#define SE second
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
#define MT make_tuple
typedef tuple<int, int, int> iii;
#define ALL(_a) _a.begin(), _a.end()
#define pb emplace_back
typedef vector<int> vi;
typedef vector<ii> vii;
#define INF 1000000005
#define LINF 1000000000000000005
#define MOD 1000000007
#define MAXN 1000005
// make t[i] non-decreasing
// define dp[i] as the minimum sum of waiting time up to i with the group ending at i
// dp[i] = for all 0 <= j <= i min(dp[j - 1] + t[i] * (n - j) = (-t[i] * j + dp[j - 1]) + t[i] * n
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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Compilation message (stderr)

Discharging.cpp: In function 'int main()':
Discharging.cpp:64:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   64 |  scanf("%d", &n);
      |  ~~~~~^~~~~~~~~~
Discharging.cpp:65:25: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   65 |  REP (i, 1, n + 1) scanf("%d", &t[i]);
      |                    ~~~~~^~~~~~~~~~~~~

• Subtask 1: 9 / 9
• Subtask 2: 13 / 13
• Subtask 3: 25 / 25
• Subtask 4: 11 / 11
• Subtask 5: 14 / 14
• Subtask 6: 28 / 28