#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <vector>
using namespace std;
struct A
{
int l,r;
int nxl,nxr;
pair < int , int > ans;
}Node[1000005];
int all[200005],now=1;
int ans[200005];
int l[200005],r[200005];
vector < pair < int , int > > query[200005];
int x[200005],y[200005];
vector < pair < int , int > > in[200005];
vector < pair < int , int > > out[200005];
pair < int , int > operator+(pair < int , int > a,pair < int , int > b)
{
return make_pair(max(a.first,b.first),min(a.second,b.second));
}
void build(int l,int r,int here)
{
Node[here].l=l;
Node[here].r=r;
if(l==r)
{
Node[here].ans=make_pair(0,2e9);
return;
}
Node[here].nxl=now++;
Node[here].nxr=now++;
build(l,(l+r)/2,Node[here].nxl);
build((l+r)/2+1,r,Node[here].nxr);
Node[here].ans=Node[Node[here].nxl].ans+Node[Node[here].nxr].ans;
}
void cha(int where,pair < int , int > con,int here)
{
if(where==Node[here].l&&where==Node[here].r)
{
Node[here].ans=con;
return;
}
if(where<=(Node[here].l+Node[here].r)/2) cha(where,con,Node[here].nxl);
else cha(where,con,Node[here].nxr);
Node[here].ans=Node[Node[here].nxl].ans+Node[Node[here].nxr].ans;
}
pair < int , int > Find(int l,int r,int here)
{
if(l==Node[here].l&&r==Node[here].r) return Node[here].ans;
if(r<=(Node[here].l+Node[here].r)/2) return Find(l,r,Node[here].nxl);
else if(l>(Node[here].l+Node[here].r)/2) return Find(l,r,Node[here].nxr);
else return Find(l,(Node[here].l+Node[here].r)/2,Node[here].nxl)+Find((Node[here].l+Node[here].r)/2+1,r,Node[here].nxr);
}
pair < int , int > tt;
int main()
{
int N,M,ok=0,i,j;
scanf("%d",&N);
for(i=1;i<=N;i++)
{
scanf("%d %d %d",&all[i],&l[i],&r[i]);
if(i-l[i]>=1)
{
in[max(1,i-r[i])].push_back(make_pair(i,all[i]));
out[i-l[i]+1].push_back(make_pair(i,all[i]));
}
}
scanf("%d",&M);
for(i=0;i<M;i++)
{
scanf("%d %d",&x[i],&y[i]);
}
build(1,N,0);
for(i=1;i<=N;i++)
{
for(auto j:in[i]) cha(j.first,make_pair(j.second,j.second),0);
for(auto j:out[i]) cha(j.first,make_pair(0,2e9),0);
for(j=0;j<M;j++)
{
if(i>=x[j]&&i+l[i]<=y[j])
{
tt=Find(i+l[i],min(y[j],i+r[i]),0);
if(tt.first) ans[j]=max(ans[j],abs(all[i]-tt.first));
if(tt.second!=2000000000) ans[j]=max(ans[j],abs(all[i]-tt.second));
}
}
}
for(i=0;i<M;i++)
{
if(ans[i]==0) printf("-1\n");
else printf("%d\n",ans[i]);
}
return 0;
}
