이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
#include "shortcut.h"
#define fi first
#define se second
using namespace std;
const int N=1e6;
const long long INF=1e15;
int w[N+10];
int dd[N+10];
long long pref[N+10];
long long suf[N+10];
long long mx[N+10];
long long tab[N+10][2];
inline bool check(int n,int c,long long x,int a,int b)
{
for(int i=1;i<=n;i++)
{
for(int j=i+1;j<=n;j++)
{
if(w[i]+w[j]+min({pref[j]-pref[i],abs(pref[j]-pref[a])+abs(pref[i]-pref[b])+c,
abs(pref[i]-pref[a])+abs(pref[j]-pref[b])+c}) > x)
return false;
}
}
return true;
}
bool ok(int n,int c,long long x)
{
for(int i=1;i<=n;i++)
{
for(int j=i;j<=n;j++)
{
if(check(n,c,x,i,j))
return true;
}
}
return false;
}
bool okk(int n,int c,long long x)
{
int i,j;
long long mx1,mx2;
for(i=1;i<=n;i++)
{
tab[i][0]=0;
tab[i][1]=0;
}
mx1=mx2=-INF;
for(i=1;i<=n;i++)
mx[i]=max(mx[i-1],w[i]-pref[i]);
for(i=n;i>=1;i--)
{
if(mx2-pref[i]+w[i]>x)
{
mx1=max(mx1,mx2+w[i]+pref[i]);
tab[i][0]=max({tab[i][0],mx1-pref[i]+c-x,mx2+mx[i]+pref[i]+c-x});
}
mx2=max(mx2,w[i]+pref[i]);
}
mx1=mx2=-INF;
for(i=n;i>=1;i--)
mx[i]=max(mx[i+1],w[i]-suf[i]);
for(i=1;i<=n;i++)
{
if(mx2-suf[i]+w[i]>x)
{
mx1=max(mx1,mx2+w[i]+suf[i]);
tab[i][1]=max({tab[i][1],mx1-suf[i]+c-x,mx2+mx[i]+suf[i]+c-x});
}
mx2=max(mx2,w[i]+suf[i]);
}
vector<pair<long long,int>> tmp;
for(i=1;i<=n;i++)
tmp.push_back({tab[i][0],i});
sort(tmp.begin(),tmp.end());
j=1;
for(auto v:tmp)
{
while(j<n && pref[j]<v.fi)
j++;
//cerr<<"l: "<<v.se<<" "<<j<<" ("<<v.fi<<")\n";
if(check(n,c,x,v.se,j))
return true;
}
tmp.clear();
for(i=1;i<=n;i++)
tmp.push_back({tab[i][1],i});
sort(tmp.begin(),tmp.end());
j=n;
for(auto v:tmp)
{
while(j>1 && suf[j]<v.fi)
j--;
//cerr<<"r: "<<v.se<<" "<<j<<" ("<<v.fi<<")\n";
if(check(n,c,x,v.se,j))
return true;
}
return false;
}
long long find_shortcut(int n,vector<int> l,vector<int> d,int c)
{
for(int i=0;i<n;i++)
w[i+1]=d[i];
for(int i=0;i<n-1;i++)
dd[i+2]=l[i];
for(int i=1;i<=n;i++)
pref[i]=pref[i-1]+dd[i];
for(int i=n;i>=1;i--)
suf[i]=suf[i+1]+dd[i+1];
long long bg,en,mid;
bg=0;
en=1e16;
while(bg<en)
{
mid=(bg+en)/2;
if(ok(n,c,mid))
en=mid;
else
bg=mid+1;
}
return bg;
}
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