Submission #368493

#TimeUsernameProblemLanguageResultExecution timeMemory
368493jainbot27Kitchen (BOI19_kitchen)C++17
100 / 100
35 ms896 KiB
#include <bits/stdc++.h> using namespace std; #define f first #define s second #define pb push_back #define ar array #define all(x) x.begin(), x.end() #define siz(x) (int)x.size() #define FOR(x, y, z) for(int x = (y); x < (z); x++) #define ROF(x, z, y) for(int x = (y-1); x >= (z); x--) #define F0R(x, z) FOR(x, 0, z) #define R0F(x, z) ROF(x, 0, z) #define trav(x, y) for(auto&x:y) using ll = long long; using vi = vector<int>; using vl = vector<long long>; using pii = pair<int, int>; using vpii = vector<pair<int, int>>; template<class T> inline bool ckmin(T&a, T b) {return b < a ? a = b, 1 : 0;} template<class T> inline bool ckmax(T&a, T b) {return b > a ? a = b, 1 : 0;} mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const char nl = '\n'; const int mxN = 305; const int MOD = 1e9 + 7; const long long infLL = 1e18; int n, m, k; int a[mxN], b[mxN]; int dp[mxN*mxN]; void no(){ cout << "Impossible\n"; exit(0); } int32_t main(){ ios_base::sync_with_stdio(0); cin.tie(0); cin >> n >> m >> k; F0R(i, n) cin >> a[i]; F0R(i, m) cin >> b[i]; if(*min_element(a, a+n)<k) no(); F0R(i, mxN*mxN) dp[i] = -MOD; dp[0] = 0; F0R(i, m){ R0F(j, mxN*mxN-b[i]){ ckmax(dp[j+b[i]], dp[j]+min(n, b[i])); } } FOR(i, accumulate(a, a+n, 0), mxN*mxN){ if(dp[i] >= n*k){ cout << i-accumulate(a, a+n, 0) << nl; return 0; } } no(); return 0; }
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