This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#pragma GCC optimize("-Ofast")
//#pragma GCC optimize("trapv")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,sse4.2,popcnt,abm,mmx,avx2,tune=native")
#pragma GCC optimize("-ffast-math")
#pragma GCC optimize("-funroll-loops")
using namespace std;
#define vi vector<int>
#define vll vector<ll>
#define vii vector<pair<int, int>>
#define pii pair<int, int>
#define pll pair<ll, ll>
#define pb push_back
#define f first
#define s second
#define sz(_) ((int)_.size())
#define all(_) _.begin(), _.end()
#define lb lower_bound
#define ub upper_bound
#define inc(i, l, r) for (int i = l; i <= r; i++)
#define dec(i, l, r) for (int i = l; i >= r; i--)
using ll = long long;
using ld = long double;
const int N = 1e5 + 7;
const ll mod = 1e9 + 7;
const int M = (1 << 10);
int n;
int cnt[M * M];
int dp[M][M][21];
int ans[N];
vi a, b;
bool chk(int i, int j)
{
return __builtin_popcount((a[i] & a[j])) == b[j];
}
void solve(int ix)
{
for (int i = ix - 1; ~i; --i)
{
if (chk(i, ix) && ans[i] + 1 == ans[ix])
{
solve(i);
break;
}
}
cout << ix + 1 << " ";
}
pii num(int x)
{
return {x >> 10, x % (1 << 10)};
}
void out(int x)
{
for (int i = 9; ~i; --i)
{
cout << !!(x & (1 << i));
}
cout << " ";
}
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0);
#ifndef ONLINE_JUDGE
#endif
cin >> n;
a.resize(n), b.resize(n);
for (auto &u : a)
cin >> u;
for (auto &u : b)
cin >> u;
for (int i = 1; i < M * M; ++i)
cnt[i] = __builtin_popcount(i);
int mx = 0, ix = 0;
for (int i = 0; i < n; ++i)
{
pii x = num(a[i]);
int ret = 1;
for (int j = 0; j < (1 << 10); ++j)
{
int sh1 = __builtin_popcount((x.f & j));
int rem = b[i] - sh1;
if (sh1 > b[i] || rem > 10)
{
continue;
}
ret = max(ret, dp[j][x.s][rem] + 1);
}
for (int j = 0; j < M; ++j)
{
int sh2 = __builtin_popcount((j & x.s));
dp[x.f][j][sh2] = max(dp[x.f][j][sh2], ret);
}
if (ret > mx)
{
mx = ret;
ix = i;
}
ans[i] = ret;
}
cout << mx << "\n";
solve(ix);
return 0;
}
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