Submission #367527

#TimeUsernameProblemLanguageResultExecution timeMemory
367527mohamedsobhi777Longest beautiful sequence (IZhO17_subsequence)C++14
23 / 100
6029 ms2540 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #pragma GCC optimize("-Ofast") //#pragma GCC optimize("trapv") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,sse4.2,popcnt,abm,mmx,avx2,tune=native") #pragma GCC optimize("-ffast-math") #pragma GCC optimize("-funroll-loops") using namespace std; using namespace __gnu_pbds; #define vi vector<int> #define vll vector<ll> #define vii vector<pair<int, int>> #define vvi vector<vi> #define vvii vector<vii> #define pii pair<int, int> #define pll pair<ll, ll> #define loop(_) for (int __ = 0; __ < (_); ++__) #define forn(i, n) for (int i = 0; i < n; ++i) #define pb push_back #define f first #define s second #define sz(_) ((int)_.size()) #define all(_) _.begin(), _.end() #define uni(_) unique(_) #define lb lower_bound #define ub upper_bound #define si set<int> #define ms multiset<int> #define qi queue<int> #define pq prioriry_queue<int> #define mi map<int, int> #define inc(i, l, r) for (int i = l; i <= r; i++) #define dec(i, l, r) for (int i = l; i >= r; i--) using lll = __int128; using ll = long long; using ld = long double; const int N = 1e5 + 7; const ll mod = 1e9 + 7; const ll inf = 2e18; auto ra = [] {char *p = new char ; delete p ; return ll(p) ; }; mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count() * (ra() | 1)); typedef tree<pii, null_type, less<pii>, rb_tree_tag, tree_order_statistics_node_update> os; int n; int main() { ios_base::sync_with_stdio(0); cin.tie(0); #ifndef ONLINE_JUDGE #endif cin >> n; vi a(n), b(n); for (auto &u : a) cin >> u; for (auto &u : b) cin >> u; auto ok = [&](int i, int j) -> bool { return __builtin_popcount((a[i] & a[j])) == b[j]; }; vi dp(n + 1, 0), prv(n + 1, -1); for (int i = 0; i < n; ++i) { dp[i] = 1; for (int j = 0; j < i; ++j) { if (ok(j, i)) { if (dp[j] + 1 > dp[i]) { dp[i] = dp[j] + 1; prv[i] = j; } } } } int Max = *max_element(all(dp)); vi ans; for (int i = 0; i < n; ++i) { if (dp[i] == Max) { int lst = i; ans.pb(i); for (int j = i - 1; ~j; --j) { if (ok(j, lst) && dp[j] == dp[lst] - 1) { ans.pb(j); lst = j; } } break; } } cout << sz(ans) << "\n"; while (sz(ans)) { cout << ++ans.back() << " "; ans.pop_back(); } return 0; }
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