//#pragma GCC target("avx2")
//#pragma GCC optimization("O3")
//#pragma GCC optimization("unroll-loops")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define pii pair<int, int>
#define pll pair<ll, ll>
#define ff first
#define ss second
#define pb push_back
#define SZ(x) ((int)(x).size())
#define all(x) x.begin(), x.end()
#define rep(i, a, b) for(int i = (a); i < (b); i++)
#define per(i, a, b) for(int i = (a); i >= (b); i--)
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int MAXK = 200+10;
const int MAXN = 2e5+100;
int N, K, a[MAXN], opt[MAXN][MAXK];
ll pr[MAXN], dp[MAXN][MAXK];
int ck;
long double slope(int i, int j){
return (long double) ((dp[i][ck] - pr[i] * pr[N]) - (dp[j][ck] - pr[j] * pr[N])) / (pr[j] - pr[i]);
}
void solve(){
cin >> N >> K;
rep(i, 1, N + 1){
cin >> a[i];
pr[i] = pr[i - 1] + a[i];
}
rep(k, 1, K + 1){
ck = k - 1;
deque<int> q;
q.push_back(0);
rep(i, 1, N + 1){
while(SZ(q) > 1 && slope(q[0], q[1]) <= pr[i]){
q.pop_front();
}
int j = q[0];
dp[i][k] = dp[j][k - 1] + (pr[i] - pr[j]) * (pr[N] - pr[i]);
opt[i][k] = j;
while(SZ(q) > 1 && slope(q[SZ(q) - 2], q.back()) <= slope(q.back(), i)){
q.pop_back();
}
q.push_back(i);
}
}
ll ans = 0; int ind = 0;
rep(i, 1, N){
if(dp[i][K] >= ans){
ans = dp[i][K], ind = i;
}
}
cout << ans << "\n";
per(k, K, 1){
cout << ind << " ";
ind = opt[ind][k];
}
}
int main(){
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
solve();
return 0;
}
