Submission #366486

#	Time	Username	Problem	Language	Result	Execution time	Memory
366486		kartel	Tenis (COCI20_tenis)	C++14	0 / 110	2 ms	364 KiB

tenis

#include <bits/stdc++.h>
#define in(x) freopen(x, "r", stdin)
#define out(x) freopen(x, "w", stdout)
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("-O3")
#define F first
#define S second
#define pb push_back
#define M ll(1e9 + 7)
#define sz(x) (int)x.size()
#define re return
#define oo ll(1e18)
#define el '\n'
#define pii pair <int, int>
#define all(x) (x).begin(), (x).end()
#define arr_all(x, n) (x + 1), (x + 1 + n)
#define vi vector<int>
#define eps (ld)1e-6
using namespace std;
//using namespace __gnu_pbds;
//typedef tree <int, null_type, less_equal <int> , rb_tree_tag, tree_order_statistics_node_update> ordered_set;
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
typedef short int si;

const int N = 3e3 + 50;

int ans[N], cnt[4], ps[N][3], n;
int a[3][N];

int main()
{
//    srand(time(0));
	ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);

//    in("turtle.in");
//    out("turtle.out");
//    inf("input.txt");
//    out("output.txt");

    cin >> n;

    for (int i = 0; i < 3; i++) {
        for (int j = 1; j <= n; j++) {
            cin >> a[i][j];
            ps[a[i][j]][i] = j;
        }
    }

    for (int i = 1; i <= n; i++)
    for (int j = i + 1; j <= n; j++) {
        int mn = 1e9;
        for (int k = 0; k < 3; k++)
            mn = min(mn, min(ps[i][k], ps[j][k]));

        int cnt1 = 0, last;

        for (int k = 0; k < 3; k++) {
            if (ps[i][k] == mn || ps[j][k] == mn)
                cnt1++, last = k;
        }

        if (cnt1 == 1) {
            cnt[last]++;
            ans[i] += (ps[i][last] < ps[j][last]);
            ans[j] += (ps[j][last] < ps[i][last]);
            continue;
        }

        mn = 1e9;

        for (int k = 0; k < 3; k++) {
            if (ps[i][k] < ps[j][k])
                mn = min(mn, ps[j][k]);
            else
                mn = min(mn, ps[i][k]);
        }

        for (int k = 0; k < 3; k++) {
            if (ps[i][k] < ps[j][k]) {
                if (ps[j][k] == mn) {
                    cnt[k]++;
                    ans[i]++;
                    break;
                }
            } else {
                if (ps[i][k] == mn) {
                    cnt[k]++;
                    ans[j]++;
                    break;
                }
            }
        }
    }

    for (int i = 0; i < 3; i++)
        cout << cnt[i] << " ";
    cout << el;

    for (int i = 1; i <= n; i++) {
        cout << ans[i] << " ";
    }
}

• Subtask 1: 0 / 35
• Subtask 2: 0 / 15
• Subtask 3: 0 / 60