Submission #366461

#TimeUsernameProblemLanguageResultExecution timeMemory
366461VimmerPapričice (COCI20_papricice)C++14
50 / 110
669 ms47596 KiB
#include <bits/stdc++.h> //#include <ext/pb_ds/assoc_container.hpp> //#include <ext/pb_ds/tree_policy.hpp> //#pragma GCC optimize("-O3") //#pragma GCC optimize("unroll-loops") //#pragma GCC optimize("-Ofast") #define N 200500 #define NN 205000 #define PB push_back #define endl '\n' #define pri(x) cout << x << endl #define _ << " " << #define all(x) x.begin(), x.end() #define sz(x) int(x.size()) #define M ll(1e9 + 7) #define F first #define S second using namespace std; //using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef short int si; typedef unsigned long long ull; //typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set; vector <int> g[N]; int ans = 1e9, siz[N], n; set <int> se[N]; set <pair <int, int> > st; void rec(int v, int p) { siz[v] = 1; for (auto it : g[v]) { if (it == p) continue; rec(it, v); siz[v] += siz[it]; } } void dfs(int v, int p) { int val = (n + 3 * siz[v] + 1) / 2; if (sz(st)) { int kol = 100; auto itr = st.lower_bound({val, -1}); if (itr == st.end()) itr--; while (kol && sz(st)) { int vt = (*itr).F; int a1 = n - siz[v] - vt, a2 = siz[v], a3 = vt; int val = max(a1, max(a2, a3)) - min(a1, min(a2, a3)); ans = min(ans, val); kol--; if (itr == st.begin()) break; itr--; } } for (auto it : g[v]) { if (it == p) continue; dfs(it, v); if (sz(se[it]) > sz(se[v])) swap(se[it], se[v]); for (auto itr : se[it]) se[v].insert(itr); } int kol = 100; if (sz(se[v])) { auto it = se[v].lower_bound(val); if (it == se[v].end()) it--; while (kol && sz(se[v])) { int vt = (*it); int a1 = n - siz[v], a2 = siz[v] - vt, a3 = vt; ans = min(ans, max(a1, max(a2, a3)) - min(a1, min(a2, a3))); kol--; if (it == se[v].begin()) break; it--; } } se[v].insert(siz[v]); st.insert({siz[v], v}); } int main() { ios_base::sync_with_stdio(0); istream::sync_with_stdio(0); cin.tie(0); cout.tie(0); // freopen("1.in", "r", stdin); cin >> n; for (int i = 1; i < n; i++) { int x, y; cin >> x >> y; g[x].PB(y); g[y].PB(x); } rec(1, -1); dfs(1, -1); pri(ans); }
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