This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#pragma GCC optimize("Ofast,unroll-loops")
#pragma GCC target("avx,avx2,sse,sse2")
#ifdef EVAL
#include"popa.h"
#endif
#include<bits/stdc++.h>
#define all(x) begin(x), end(x)
using namespace std;
using ll = long long;
namespace local {
int ar[10010], qc = 0;
int query(int a, int b, int c, int d) {
qc++;
int x = 0, y = 0;
for(;a<=b;a++) x = __gcd(x, ar[a]);
for(;c<=d;c++) y = __gcd(y, ar[c]);
return x==y;
}
};
#ifndef EVAL
using namespace local;
#endif
int solve(int n, int *L, int *R) {
vector<int> st {0};
int rt = 0;
vector<int> start(n);
for(int i = 0; i < n; i++) L[i] = R[i] = -1;
for(int i = 1; i < n; i++) {
int ins = 0;
while(st.size()) {
int v = st.back();
if(R[v] == -1) {//try becoming right child
if(query(start[v], i, v, v)) {//possible
R[v] = i;
start[i] = i;
ins = 1;break;
} else {
st.pop_back();
}
} else {//try putting right child as my left child
int vr = R[v];
if(query(start[vr], i, i, i)) {
R[v] = i;
L[i] = vr;
start[i] = start[vr];
ins = 1;break;
} else {
st.pop_back();
}
}
}
if(!ins) {
L[i] = rt;
start[i] = 0;
rt = i;
}
st.push_back(i);
}
return rt;
}
#ifndef EVAL
int main() {
cin.tie(0)->sync_with_stdio(0);
//multitest([&](){});
int n;
cin >> n;
for(int i = 1; i <= n; i++) cin >> ar[i];
vector<int> L(n), R(n);
cout << solve(n, L.data(), R.data()) << endl;
for(int i = 0; i < n; i++) cout << L[i] << " " << R[i] << '\n';
cout << " :: " << qc << endl;
}
#endif
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