Submission #365355

#	Time	Username	Problem	Language	Result	Execution time	Memory
365355		IsaacMoris	Džumbus (COCI19_dzumbus)	C++14	110 / 110	160 ms	13164 KiB

dzumbus

// Sometimes, the questions are complicated - and the answers are simple. //
#include<iostream>
#include <bits/stdc++.h>
#define ll long long
#define ld  long double
#define IO ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
using namespace std;
const int N = 1e3 + 5, inf = 1e9 + 2;
int n, m, q, D[N];
vector<int> adj[N];
bool visited[N];
int dp[N][N][3];
int sz[N];
void dfs(int node, int p) {
    if(visited[node])
        return;
    visited[node] = true;
    sz[node] = 1;

    for(int i = 0; i <= n; i++)
        for(int j = 0; j < 3; j++)
            dp[node][i][j] = inf;

    dp[node][0][0] = 0;
    dp[node][1][1] = D[node];
    dp[node][0][1] = inf;

    for(auto i : adj[node])
        if(i != p) {
            int child = i;
            dfs(child, node);

            for(int j = sz[node]; j >= 0; j--) {
                for(int k = 1; k <= sz[child]; k++) {

                    dp[node][j + k][0] = min(dp[node][j + k][0], dp[node][j][0] + dp[child][k][0]);
                    dp[node][j + k][0] = min(dp[node][j + k][0], dp[node][j][0] + dp[child][k][2]);

                    //----------------------------------------------------------------------------------------
                    dp[node][j + k][2] = min(dp[node][j + k][2], dp[node][j][2] + dp[child][k][0]);
                    dp[node][j + k][2] = min(dp[node][j + k][2], dp[node][j][2] + dp[child][k][1]);
                    dp[node][j + k][2] = min(dp[node][j + k][2], dp[node][j][2] + dp[child][k][2]);

                    dp[node][j + k][2] = min(dp[node][j + k][2], dp[node][j][1] + dp[child][k][1]);
                    dp[node][j + k][2] = min(dp[node][j + k][2], dp[node][j][1] + dp[child][k][2]);

                    dp[node][j + k][1] = min(dp[node][j + k][1], dp[node][j][1] + dp[child][k][0]);
                    dp[node][j + k][1] = min(dp[node][j + k][1], dp[node][j][1] + dp[child][k][2]);

                }
            }
            sz[node] += sz[child];
        }
}
int main() {
    IO
    cin >> n >> m;
    for(int i = 1; i <= n; i++)
        cin >> D[i];
    for(int i = 1; i <= m; i++) {
        int x, y;
        cin >> x >> y;
        adj[x].push_back(y);
        adj[y].push_back(x);
    }
    D[0] = inf;
    for(int i = 1; i <= n; i++)
        if(!visited[i]) {
            dfs(i, 0);
            adj[0].push_back(i);
        }
    dfs(0, 0);
    cin >> q;
    while(q--) {
        int s;
        cin >> s;
        for(int i = n; i >= 0; i--)
            if(dp[0][i][0] <= s) {
                cout << i << "\n";
                break;
            }
    }
}

• Subtask 1: 20 / 20
• Subtask 2: 30 / 30
• Subtask 3: 30 / 30
• Subtask 4: 30 / 30