Submission #361590

#	Time	Username	Problem	Language	Result	Execution time	Memory
361590		iliccmarko	Fishing Game (RMI19_fishing)	C++14	0 / 100	178 ms	215076 KiB

fishing

#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define endl "\n"
#define INF 1000000000
#define LINF 1000000000000000LL
#define pb push_back
#define all(x) x.begin(), x.end()
#define len(s) (int)s.size()
#define test_case { int t; cin>>t; while(t--)solve(); }
#define single_case solve();
#define line cerr<<"----------"<<endl;
#define ios { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); cerr.tie(NULL); }
#define mod 1000000007LL
const int N = 305;
ll dp[N][N][N];
ll a[N], b[N], c[N];

ll resi(ll x, ll y, ll z)
{
    //cout<<x<<" "<<y<<" "<<z<<endl;
    if(x<0||y<0||z<0) return 0;
    if(dp[x][y][z]!=-1) return dp[x][y][z];
    dp[x][y][z] = (z*x*z*resi(x-1, y+1, z-1))%mod;
    dp[x][y][z] = (dp[x][y][z] + z*(y+1)*y*resi(x+1, y-1, z-1))%mod;
    dp[x][y][z] = (dp[x][y][z] + x*(x-1)*y*resi(x-1, y-1, z+1))%mod;
    dp[x][y][z] = (dp[x][y][z] + x*y*(y-1)*resi(x, y-2, z))%mod;
    dp[x][y][z] = (dp[x][y][z] + x*(x-1)*z*resi(x-2, y, z))%mod;
    dp[x][y][z] = (dp[x][y][z] + z*(y+1)*(z-1)*resi(x, y, z-2))%mod;
    dp[x][y][z] = (dp[x][y][z] + x*y*z*resi(x-1, y-1, z-1))%mod;
    return dp[x][y][z];
}



int main()
{
    ios
    ll n, t;
    cin>>n>>t;
    for(int i = 0;i<3*n+2;i++)for(int j = 0;j<3*n+2;j++)for(int z = 0;z<3*n+2;z++) dp[i][j][z] = -1;
    dp[0][0][0] = 1;
    while(t--)
    {
       //for(int i = 0;i<3*n+2;i++)for(int j = 0;j<3*n+2;j++)for(int z = 0;z<3*n+2;z++) dp[i][j][z] = -1;
       for(int i = 0;i<N;i++) a[i] = b[i] = c[i] = 0;
       for(int i = 0;i<2*n;i++)
       {
           ll x;
           cin>>x;
           a[x]++;
       }
       for(int i = 0;i<2*n;i++)
       {
           ll x;
           cin>>x;
           b[x]++;
       }
       for(int i = 0;i<2*n;i++)
       {
           ll x;
           cin>>x;
           c[x]++;
       }
       ll x, y, z;
       x = y = z = 0;
       for(int i = 1;i<=3*n;i++) if(a[i]&&b[i]) x++;
       for(int i = 1;i<=3*n;i++) if(b[i]&&c[i]) y++;
       for(int i = 1;i<=3*n;i++) if(a[i]&&c[i]) z++;
       cout<<resi(x, y, z)<<endl;
    }





    return 0;
}

• Subtask 1: 0 / 100