Submission #354295

#	Time	Username	Problem	Language	Result	Execution time	Memory
354295		parsabahrami	Toll (BOI17_toll)	C++11	0 / 100	0 ms	256 KiB

toll

// Call my Name and Save me from The Dark
#include <bits/stdc++.h>
 
using namespace std;

typedef long long int ll;
typedef pair<int, int> pii;
 
#define SZ(x)                       (int) x.size()
#define F                           first
#define S                           second

const int N = 5e4 + 10, MOD = 1e9 + 7;
//int M[N], dp[18][5][N], n, k, q, m; vector<pii> in[N], out[N];
/* 
void divide(int l = 0, int r = (n - 1) / k + 1, int h = 0) {
    if (r - l < 3) return;
    int mid = (l + r) >> 1;
    //printf("l %d mid %d r %d\n", l, mid, r);
    for (int i = mid * k; i < mid * k + k; i++) dp[h][i % k][i] = 0;
    for (int i = mid * k - 1; i >= l * k; i--) {
        for (int j = 0; j < 5; j++) for (pii u : out[i]) {
            dp[h][j][i] = min(dp[h][j][i], dp[h][j][u.F] + u.S);
        }
    }
    for (int i = mid * k + k; i < min(n, r * k); i++) {
        for (int j = 0; j < 5; j++) for (pii u : in[i]) {
            dp[h][j][i] = min(dp[h][j][i], dp[h][j][u.F] + u.S);
        }
    }
    for (int i = mid; i < r; i++) M[i] ^= 1 << h;
    //for (int i = l * k; i < min(n, r * k); i++) for (int j = 0; j < 5; j++) printf("i %d j %d dp %d\n", i, j, dp[h][j][i]);
    divide(l, mid), divide(mid, r);
}*/ 

int main() {/* 
    for (int i = 0; i < 18; i++) for (int j = 0; j < 5; j++) fill(dp[i][j], dp[i][j] + N, MOD);
    scanf("%d%d%d%d", &k, &n, &m, &q);
    for (int i = 0; i < m; i++) {
        int u, v, w; scanf("%d%d%d", &u, &v, &w);
        out[u].push_back({v, w});
        in[v].push_back({u, w});
    }
    divide();
    for (; q; q--) {
        int a, b; scanf("%d%d", &a, &b);
        if (a == b) printf("%d\n", 0);
        else if (a / k == b / k) printf("-1\n");
        else if (b / k - a / k == 1) {
            int ret = -1;
            for (pii u : out[a])  if (u.F == b) ret = u.S;
            printf("%d\n", ret);
        } else {
            int h = __builtin_ctz(M[a / k] ^ M[b / k]);
            int ret = MOD;
            for (int i = 0; i < 5; i++) {
                ret = min(ret, dp[h][i][a] + dp[h][i][b]);
            }
            printf("%d\n", ret == MOD ? -1 : ret);
        }
    }*/ 
    return 0;
}

• Subtask 1: 0 / 7
• Subtask 2: 0 / 10
• Subtask 3: 0 / 8
• Subtask 4: 0 / 31
• Subtask 5: 0 / 44