Submission #353651

#	Time	Username	Problem	Language	Result	Execution time	Memory
353651		SavicS	Miners (IOI07_miners)	C++14	100 / 100	98 ms	1000 KiB

miners

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>

#define fi first
#define se second
#define pb push_back
#define sz(a) (int)a.size()
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define ff(i,a,b) for(int i=a;i<=b;i++)
#define fb(i,b,a) for(int i=b;i>=a;i--)

using namespace std;
using namespace __gnu_pbds;
typedef long long ll;
typedef pair<int,int> pii;
const int maxn = 100005;
const int inf = 1e9 + 5;

template<typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

// os.order_of_key(k) the number of elements in the os less than k
// *os.find_by_order(k)  print the k-th smallest number in os(0-based)

int n;
int niz[maxn];
string s;

int dp[4][4][4][4];
int pomdp[4][4][4][4];
int pom[4][4][4];

int calc(int x, int y, int z){
    set<int> poms;
    if(x)poms.insert(x);
    if(y)poms.insert(y);
    if(z)poms.insert(z);
    return sz(poms);
}

int main()
{
    ios::sync_with_stdio(false);
    cout.tie(nullptr);
    cin.tie(nullptr);
    cin >> n >> s;
    s = ' ' + s;
    ff(i,1,n)niz[i] = (s[i] == 'M' ? 1 : (s[i] == 'B' ? 2 : 3));
    ff(a,0,3)ff(b,0,3)ff(c,0,3)ff(d,0,3)dp[a][b][c][d] = -inf;
    ff(a,0,3)ff(b,0,3)ff(c,0,3)pom[a][b][c] = calc(a, b, c);
    dp[0][0][0][0] = 0;
    ff(i,1,n){
        ff(a,0,3)ff(b,0,3)ff(c,0,3)ff(d,0,3)pomdp[a][b][c][d] = -inf;
        int x = niz[i];
        ff(a,0,3){
            ff(b,0,3){
                ff(c,0,3){
                    ff(d,0,3){
                        pomdp[a][b][d][x] = max(pomdp[a][b][d][x], dp[a][b][c][d] + pom[c][d][x]);
                        pomdp[b][x][c][d] = max(pomdp[b][x][c][d], dp[a][b][c][d] + pom[a][b][x]);
                    }
                }
            }
        }
        ff(a,0,3)ff(b,0,3)ff(c,0,3)ff(d,0,3)dp[a][b][c][d] = pomdp[a][b][c][d];
    }
    int rez = -inf;
    ff(a,0,3){
        ff(b,0,3){
            ff(c,0,3){
                ff(d,0,3)rez = max(rez, dp[a][b][c][d]);
            }
        }
    }
    cout << rez << endl;
    return 0;
}
/**

6
MBMFFB

16
MMBMBBBBMMMMMBMB

// probati bojenje sahovski ili slicno

**/

• Subtask 1: 9 / 9
• Subtask 2: 9 / 9
• Subtask 3: 9 / 9
• Subtask 4: 9 / 9
• Subtask 5: 9 / 9
• Subtask 6: 7 / 7
• Subtask 7: 8 / 8
• Subtask 8: 8 / 8
• Subtask 9: 8 / 8
• Subtask 10: 8 / 8
• Subtask 11: 8 / 8
• Subtask 12: 8 / 8