Submission #352350

#	Time	Username	Problem	Language	Result	Execution time	Memory
352350		ryansee	Connecting Supertrees (IOI20_supertrees)	C++14	96 / 100	305 ms	23408 KiB

supertrees

#include "supertrees.h"

#include "bits/stdc++.h"
using namespace std;

#define FAST ios_base::sync_with_stdio(false); cin.tie(0);
#define pb push_back
#define eb emplace_back
#define ins insert
#define f first
#define s second
#define cbr cerr<<"hi\n"
#define mmst(x, v) memset((x), v, sizeof ((x)))
#define siz(x) ll(x.size())
#define all(x) (x).begin(), (x).end()
#define lbd(x,y) (lower_bound(all(x),y)-x.begin())
#define ubd(x,y) (upper_bound(all(x),y)-x.begin())
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());    //can be used by calling rng() or shuffle(A, A+n, rng)
inline long long rand(long long x, long long y) { return rng() % (y+1-x) + x; } //inclusivesss
string inline to_string(char c) {string s(1,c);return s;} template<typename T> inline T gcd(T a,T b){ return a==0?llabs(b):gcd(b%a,a); }

using ll=long long; 
using ld=long double;
#define FOR(i,s,e) for(ll i=s;i<=ll(e);++i)
#define DEC(i,s,e) for(ll i=s;i>=ll(e);--i)
using pi=pair<ll,ll>; using spi=pair<ll,pi>; using dpi=pair<pi,pi>; 

long long LLINF = 1e18;
int INF = 1e9+1e6;
#define MAXN (1006)

int p[MAXN];
void init() {
	FOR(i,0,MAXN-1) p[i]=i;
}
int find(int x) { return p[x] == x ? x : p[x] = find(p[x]); }
void merge(int x,int y) {
	p[find(x)] = find(y);
}

vector<vector<int>> v;
void add(int x,int y) {
	v[x][y]=v[y][x]=1;
}

int construct(std::vector<std::vector<int>> p) {
	int n = p.size();
	v.resize(n, vector<int>(n, 0));
	init();
	FOR(i,0,n-1) FOR(j,i+1,n-1) if(p[i][j]) merge(i, j);
	FOR(i,0,n-1) FOR(j,i+1,n-1) if(p[i][j]==0 && find(i)==find(j)) return 0;
	vector<vector<int>> nodes;
	FOR(i,0,n-1) if(find(i) == i) {
		nodes.pb({});
		FOR(j,0,n-1) if(find(j) == find(i)) {
			nodes.back().eb(j);
		}
	}
	init();
	for(auto i:nodes) {
		for(auto j:i) for(auto k:i) if(j^k && p[j][k] == 1) merge(j, k);
		for(auto j:i) for(auto k:i) if(j^k && p[j][k] == 2 && find(j)==find(k)) return 0;
		vector<int> tmp;
		for(auto j:i) if(find(j)==j) tmp.eb(j);
		if(siz(tmp) == 2) return 0;
		if(siz(tmp) > 1) FOR(i,0,siz(tmp)-1) add(tmp[i], tmp[(i+1)%siz(tmp)]);
		for(auto j:i) if(find(j) ^ j) add(find(j), j);
	}
	build(v);
	return 1;
}

• Subtask 1: 11 / 11
• Subtask 2: 10 / 10
• Subtask 3: 19 / 19
• Subtask 4: 35 / 35
• Subtask 5: 21 / 21
• Subtask 6: 0 / 4