Submission #347715

#	Time	Username	Problem	Language	Result	Execution time	Memory
347715		jesus_coconut	Meteors (POI11_met)	C++17	0 / 100	200 ms	35840 KiB

met

#include <bits/stdc++.h>

using namespace std;

using ll = long long;

struct st{
    int l, r;
    ll x;
};

int const N = 300010;
vector<int> own[N];
st q[N];
ll mx[N];

template<class T>
struct BIT{
    vector<T> bit;

    BIT(int N) : bit(N, 0) {}

    void add(int pos, T val) {
        for (; pos < (int) bit.size(); pos += pos & -pos) {
            bit[pos] += val;
        }
    }

    T sum(int r) {
        T res{};
        for (; r > 0; r -= r & -r) {
            res += bit[r];
        }
        return res;
    }

    T sum(int l, int r) { return sum(r) - sum(l - 1); }
};
int sol[N];

BIT<ll> bit(1);


void add(int i, int p) {
    if (q[i].l <= q[i].r) {
        bit.add(q[i].l, q[i].x * p);
        bit.add(q[i].r + 1, -q[i].x * p);
    } else {
        bit.add(1, q[i].x * p);
        bit.add(q[i].r + 1, -q[i].x * p);
        bit.add(q[i].l, q[i].x * p);
    }
}

void solve(int lo, int hi, vector<int> const &ind) {
    if (lo == hi) {
        for (int i : ind) {
            sol[i] = lo;
        }
        return;
    }

    int mid = (lo + hi) / 2;
    for (int i = lo; i <= mid; ++i) {
        add(i, 1);
    }

    vector<int> l, r;

    for (int i : ind) {
        ll suma = 0;
        for (int a : own[i]) {
            suma += bit.sum(a);
            if (suma >= mx[i]) break;
        }
        if (suma >= mx[i]) {
            l.push_back(i);
        } else r.push_back(i);
    }

    solve(mid + 1, hi, r);
    for (int i = lo; i <= mid; ++i) {
        add(i, -1);
    }
    solve(lo, mid, l);
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);

    int n, m;
    cin >> n >> m;
    bit.bit.resize(n + 10);
    for (int i = 1; i <= m; ++i) {
        int a;
        cin >> a;
        own[a].push_back(i);
    }
    for (int i = 1; i <= n; ++i) {
        cin >> mx[i];
    }
    int k;
    cin >> k;
    for (int i = 1; i <= k; ++i) {
        cin >> q[i].l >> q[i].r >> q[i].x;
    }
    vector<int> tmp(n);
    iota(begin(tmp), end(tmp), 1);
    solve(1, k + 1, tmp);

    for (int i = 1; i <= n; ++i) {
        if (sol[i] > k) {
            cout << "NIE\n";
        } else cout << sol[i] << '\n';
    }
    return 0;
}

• Subtask 1: 0 / 12
• Subtask 2: 0 / 12
• Subtask 3: 0 / 12
• Subtask 4: 0 / 12
• Subtask 5: 0 / 13
• Subtask 6: 0 / 13
• Subtask 7: 0 / 13
• Subtask 8: 0 / 13