Submission #347562

#TimeUsernameProblemLanguageResultExecution timeMemory
347562Return_0Bitaro’s Party (JOI18_bitaro)C++17
0 / 100
14 ms12012 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #pragma GCC optimize ("Ofast,unroll-loops") // #pragma GCC target ("avx,avx2,fma") using namespace std; using namespace __gnu_pbds; typedef int ll; typedef long double ld; typedef pair <ll, ll> pll; #ifdef SINA #define dbg(...) __f(#__VA_ARGS__, __VA_ARGS__) template <typename Arg1> void __f(const char* name, Arg1&& arg1) { cout << name << " : " << arg1 << std::endl; } template <typename Arg1, typename... Args> void __f (const char* names, Arg1&& arg1, Args&&... args) { const char* comma = strchr(names + 1, ',');cout.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...); } #define dbg2(x, j, n) cout<< #x << " : "; output((j), (n), x, 1); #else #define dbg(...) 0 #define dbg2(x, j, n) 0 #endif #define SZ(x) ((ll)((x).size())) #define File(s, t) freopen(s ".txt", "r", stdin); freopen(t ".txt", "w", stdout); #define input(j, n, a) for (int _i = (j); _i < (n)+(j); _i++) cin>> a[_i]; #define output(j, n, a, t) for (int _i = (j); _i < (n)+(j); _i++) cout<< a[_i] << (((t) && _i != (n)+(j)-1)? ' ' : '\n'); #define kill(x) return cout<< x << endl, 0 #define cl const ll #define fr first #define sc second #define lc (v << 1) #define rc (lc | 1) #define mid ((l + r) >> 1) #define All(x) (x).begin(), (x).end() cl inf = sizeof(ll) == 4 ? (1e9 + 10) : (3e18), mod = 1e9 + 7, MOD = 998244353; template <class A, class B> ostream& operator << (ostream& out, const pair<A, B> &a) { return out << '(' << a.first << ", " << a.second << ')'; } template <class A> ostream& operator << (ostream& out, const vector<A> &a) { if(!a.size())return cout<<"[]";cout<< '[' << a[0]; for (int i = 0; ++i < (int)(a.size());) cout<< ", " << a[i];cout<< ']'; } template <class T, typename _t = less <T> > using Tree = tree <T, null_type, _t, rb_tree_tag, tree_order_statistics_node_update>; cl N = 1e5 + 7, SQ = 300; ll pos [N], dis [N], n, m, q, ans; vector <ll> adj [N], jda [N], tops, vec; vector <pll> dp [N], tmp; bool mark [N]; void dfs (ll v) { mark[v] = 1; for (auto u : adj[v]) if (!mark[u]) dfs(u); pos[v] = n - SZ(tops) - 1, tops.push_back(v); } void _merge (vector <pll> &v, vector <pll> &u) { vector <pll> res; ll l1 = 0, l2 = 0; while (l1 < SZ(v) && l2 < SZ(u) && l1 + l2 <= SQ) { if (v[l1] == pll(u[l2].fr + 1, u[l2].sc)) res.push_back(v[l1++]), l2++; else if (v[l1].fr > u[l2].fr + 1) res.push_back(v[l1++]); else res.push_back({u[l2].fr + 1, u[l2].sc}), l2++; } while (l1 < SZ(v) && l1 + l2 <= SQ) res.push_back(v[l1++]); while (l1 < SZ(v) && l1 + l2 <= SQ) res.push_back({u[l2].fr + 1, u[l2].sc}), l2++; v.swap(res); } int main () { ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); memset(dis, -61, sizeof dis); cin>> n >> m >> q; for (ll i = 0, v, u; i < m; i++) cin>> v >> u, adj[v].push_back(u), jda[u].push_back(v); for (ll i = 1; i <= n; i++) if (!mark[i]) dfs(i); reverse(All(tops)); memset(mark, 0, sizeof mark); for (auto v : tops) { dp[v].push_back({0, v}); for (auto u : jda[v]) _merge(dp[v], dp[u]); } for (ll v, t, i; q--;) { cin>> v >> t; vec.resize(t); for (auto &x : vec) cin>> x, mark[x] = 1; if (t < SQ) { for (i = 0; i < SZ(dp[v]) && mark[dp[v][i].sc]; i++); cout<< (i < SZ(dp[v]) ? dp[v][i].fr : -1) << '\n'; } else { for (ans = -1, dis[v] = 0, i = pos[v] - 1; ~i; i--) { for (auto u : adj[tops[i]]) dis[tops[i]] = max(dis[tops[i]], dis[u] + 1); if (!mark[tops[i]]) ans = max(ans, dis[tops[i]]); } cout<< ans << '\n'; for (i = 0; i <= pos[v]; i++) dis[tops[i]] = -inf; } for (auto &x : vec) mark[x] = 0; } return 0; } /* */

Compilation message (stderr)

bitaro.cpp: In function 'std::ostream& operator<<(std::ostream&, const std::vector<_Tp>&)':
bitaro.cpp:43:6: warning: this 'if' clause does not guard... [-Wmisleading-indentation]
   43 |      if(!a.size())return cout<<"[]";cout<< '[' << a[0]; for (int i = 0; ++i < (int)(a.size());) cout<< ", " << a[i];cout<< ']';  }
      |      ^~
bitaro.cpp:43:37: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'if'
   43 |      if(!a.size())return cout<<"[]";cout<< '[' << a[0]; for (int i = 0; ++i < (int)(a.size());) cout<< ", " << a[i];cout<< ']';  }
      |                                     ^~~~
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