#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int , int> pii;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const ll maxn = 2e5 + 100;
const ll mod = 1e9+7;
const ld PI = acos((ld)-1);
#define pb push_back
#define endl '\n'
#define dokme(x) cout << x , exit(0)
#define migmig ios::sync_with_stdio(false),cin.tie(0),cout.tie(0)
#define ms(x , y) memset(x , y , sizeof x)
ll pw(ll a, ll b, ll md = mod){ll res = 1;while(b){if(b&1){res=(a*res)%md;}a=(a*a)%md;b>>=1;}return(res);}
int n , d;
vector < int > adj[maxn];
int h[maxn] , srt[maxn];
int par[maxn] , l[maxn] , r[maxn] , tim = 0;
int seg[maxn * 4];
#define lc (v << 1)
#define rc (lc | 1)
#define mid ((l + r) >> 1)
int near[maxn];
int ord[maxn];
const int inf = 1e9;
void dfs(int v , int p = 0){
par[v] = p;
l[v] = tim + 1;
tim = tim + 1;
ord[tim] = v;
for(int u : adj[v])if(u!=p)
h[u] = h[v] + 1 , dfs(u , v);
r[v] = tim;
}
bool comp(int i , int j){
return(h[i] > h[j]);
}
void build(int v = 1 , int l = 1 , int r = maxn){
if(r - l == 1){
seg[v] = inf;
return;
}
build(lc , l , mid);
build(rc , mid , r);
seg[v] = min(seg[lc] , seg[rc]);
}
void update(int L , int R , int x , int v = 1 , int l = 1 , int r = maxn){
if(R <= l or r <= L)
return;
if(L <= l and r <= R){
seg[v] = min(seg[v] , x);
return;
}
update(L , R , x , lc , l , mid);
update(L , R , x , rc , mid , r);
}
int query(int x , int v = 1 , int l = 1 , int r = maxn){
int ans = seg[v];
for(; r - l > 1;){
if(x < mid)
v = lc , r = mid;
else
v = rc , l = mid;
ans = min(ans , seg[v]);
}
return(ans);
}
int32_t main(){
migmig;
cin >> n >> d;
for(int i = 2 ; i <= n ; i ++){
int x;
cin >> x;
adj[x + 1].pb(i);
adj[i].pb(x+1);
}
dfs(1);
h[0] = -1;
for(int i = 1 ; i <= n ; i ++)
srt[i] = i , near[i] = inf;
build();
sort(srt + 1 , srt + n + 1 , comp);
int ans = 0;
for(int i = 1 ; i <= n ; i ++){
int v = srt[i];
if(l[v] > n or l[v] < 1)continue;
if(query(l[v]) + h[v] < d)continue;
ans++;
int p = v;
for( ; v ; ){
near[v] = min(near[v] , h[p]);
update(l[v] , r[v] + 1 , near[v] - 2*h[v]);
v = par[v];
}
}
cout << ans;
return(0);
}
