Submission #34543

#	TimeUTC-0	Username	Problem	Language	Result	Execution time	Memory
34543	2017-11-12 08:20:17	cheater2k	Watching (JOI13_watching)	C++14	100 / 100	66 ms	17748 KiB

watching

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#include <bits/stdc++.h>
using namespace std;
const int N = 2005;
int n, p, q;
long long a[N];
int to1[N], to2[N];
int f[N][N];
bool check(int w) {
  int pt = 1;
  for (int i = 1; i <= n; ++i) {
    while(pt <= n && a[i] + w - 1 >= a[pt]) ++pt; --pt;
    to1[i] = pt;
  }
  pt = 1;
  for (int i = 1; i <= n; ++i) {
    while(pt <= n && a[i] + 2LL * w - 1 >= a[pt]) ++pt; --pt;
    to2[i] = pt;
  }
  for (int i = 0; i <= p; ++i) {
    for (int j = 0; j <= q; ++j) {
      f[i][j] = 0;
      if (i > 0) f[i][j] = max(f[i][j], to1[f[i-1][j] + 1]);
      if (j > 0) f[i][j] = max(f[i][j], to2[f[i][j-1] + 1]);
      if (f[i][j] >= n) return true;
    }
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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Compilation message (stderr)

watching.cpp: In function 'int main()':
watching.cpp:41:48: warning: format '%d' expects argument of type 'int*', but argument 2 has type 'long long int*' [-Wformat=]
  for (int i = 1; i <= n; ++i) scanf("%d", &a[i]);
                                                ^
watching.cpp:37:31: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d %d %d", &n, &p, &q);
                               ^
watching.cpp:41:49: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  for (int i = 1; i <= n; ++i) scanf("%d", &a[i]);
                                                 ^

• Subtask 1: 50 / 50
• Subtask 2: 50 / 50