Submission #343624

#	Time	Username	Problem	Language	Result	Execution time	Memory
343624		_ani	K blocks (IZhO14_blocks)	C++17	0 / 100	1 ms	364 KiB

blocks

#define BUGO(x) cerr << #x << " = " << (x) << '\n';
#include <iostream>
#include <algorithm>
#include <stack>
using namespace std;
using ll = long long;
ll inf = 1'000'000'000'000'000'000LL;
ll dp[100'002][102], a[100'002];
ll mn[4 * 100'002][102];
struct el {
    ll x; int ind;
};
bool operator<(const el& a, const el& b) {
    return a.x < b.x;
}
void Add(int v, int vl, int vr, int k, int pos) {
    if(vl == vr){
        mn[v][k] = dp[pos][k];
        return;
    }
    int m = (vl + vr) / 2;
    if(pos <= m)
        Add(v * 2, vl, m, k, pos);
    else Add(v * 2 + 1, m + 1, vr, k, pos);
    mn[v][k] = min(mn[v * 2][k], mn[v * 2 + 1][k]);
}
ll Mn(int v, int vl, int vr, int k, int l, int r){
    if(vl == l && vr == r){
        return mn[v][k];
    }
    int m = (vl + vr) / 2;
    ll res = inf;
    if(l <= m) res = min(res, Mn(v * 2, vl, m, k, l, min(r, m)));
    if(r > m) res = min(res, Mn(v * 2 + 1, m + 1, vr, k, max(l, m + 1), r));
    return res;
}
int main()
{
	int n, k;
	cin >> n >> k;
	for (int i = 1; i <= n; i++)
		cin >> a[i];
    for(int i = 1; i <= n; i++)
        for(int curk = 1; curk <= k; curk++)
            dp[i][curk] = inf;

    for(int curk = 1; curk <= k; curk++) {
            stack<el> x;
            x.push({inf, 0});
        for(int i = 1; i <= n; i++) {
            while(x.top().x < a[i])x.pop();
            el prev = x.top();
            x.push({a[i], i});
            if(i < curk){
                Add(1, 1, n, curk, i);
                continue;
            }
            if(prev.ind == 0){
                dp[i][curk] = ((i - 1 == 0)? 0: Mn(1, 1, n, k - 1, 1, i - 1)) + a[i];
            }
            else dp[i][curk] = min(dp[prev.ind][k], Mn(1, 1, n, k - 1, prev.ind, i - 1));
            Add(1, 1, n, curk, i);
        }
    }

	/*for (int i = 0; i <= n; i++)
	{
		for (int curk = 0; curk <= k; curk++)
			cerr << dp[i][curk] << ' ';
		cerr << '\n';
	}*/
	cout << dp[n][k] << '\n';
	return 0;
}

• Subtask 1: 0 / 14
• Subtask 2: 0 / 18
• Subtask 3: 0 / 21
• Subtask 4: 0 / 47