Submission #340753

#	Time	Username	Problem	Language	Result	Execution time	Memory
340753		David_M	Red-blue table (IZhO19_stones)	C++14	0 / 100	1 ms	492 KiB

stones

#include <bits/stdc++.h> 
#define ll long long
#define pb push_back
#define F first
#define S second
using namespace std;
const ll N=1000006;
int n, m, q, o, u, e, l;
string x, y, a[1001];
 
int main(){ios_base::sync_with_stdio(false), cin.tie(0);
	cin>>q;
	while(q--){x="";o=u=0;	
		cin>>n>>m;		
		for(int i=0; i<n; i++)for(int j=0; j<m; j++)a[i][j]='-';
	
		if(n%2==1&&m%2==1){
			if(n==1){cout<<m<<endl;while(m--)cout<<'-';cout<<'\n';continue;}
			if(m==1){cout<<n<<endl;while(n--)cout<<"+\n";continue;}
			
			cout<<n+m-2<<'\n';
			
			for (int i=1; i<=m/2; i++)x+='-';
			for (int i=1; i<=m/2+1; i++)x+='+';
			for (int i=1; i<=n/2; i++)cout<<x<<'\n';
			
			for (int i=0; i<m-1; i++)x[i]='-'; x[m-1]='+';
			cout<<x<<'\n';
			
			x="";
			for (int i=1; i<=m/2; i++)x+='+';
			for (int i=1; i<=m/2; i++)x+='-';
			x+='+';
			for (int i=1; i<=n/2; i++)cout<<x<<'\n';
		}
		if(n%2==0&&m%2==0){
			if(n<m)n--,o=1;
			else m--,u=1;
		}
		e=n/2;
		if(n%2==1){
			if(m+4-2*n>=0)l=n-2;
			else l=n-3;
			for (int i=0; i<m; i++)
				for (int j=i; j<i+e; j++)
					a[j%l][i]='+';
			cout<<m+l<<endl;
			for(int i=0; i<n; i++){for(int j=0; j<m; j++)cout<<a[i][j];cout<<endl;}	
		}else{
			for(int i=0; i<n; i++)for(int j=0; j<m; j++)a[i][j]='+';
			if(n+4-2*m>=0)l=m-2;
			else l=m-3;
			for (int i=0; i<n; i++)
				for (int j=i; j<i+e; j++)
					a[i][j%l]='-';
		}	
		cout<<n*(m%2)+m*(n%2)+l<<endl;
		if(o==1)for (int i=0; i<m; i++)a[n][i]='-';
		if(u==1)for (int i=0; i<n; i++)a[i][m]='+';
		
		for(int i=0; i<n; i++){for(int j=0; j<m; j++)cout<<a[i][j];cout<<endl;}	
	}
 
}

Compilation message (stderr)

stones.cpp: In function 'int main()':
stones.cpp:27:4: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
   27 |    for (int i=0; i<m-1; i++)x[i]='-'; x[m-1]='+';
      |    ^~~
stones.cpp:27:39: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
   27 |    for (int i=0; i<m-1; i++)x[i]='-'; x[m-1]='+';
      |                                       ^

• Subtask 1: 0 / 17
• Subtask 2: 0 / 10
• Subtask 3: 0 / 16
• Subtask 4: 0 / 11
• Subtask 5: 0 / 15
• Subtask 6: 0 / 31