Submission #340100

#TimeUsernameProblemLanguageResultExecution timeMemory
340100SprdaloBootfall (IZhO17_bootfall)C++17
65 / 100
1074 ms4580 KiB
#include <bits/stdc++.h>

using namespace std;

typedef long long ll;
typedef long double ld;
typedef pair<int, int> pi;
typedef pair<ll, ll> pl;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<double> vd;
typedef vector<bool> vb;
typedef vector<char> vc;
typedef vector<string> vs;
typedef vector<pi> vp;
typedef vector<pl> vpl;

void no(){
    cout << "0\n";
    exit(0);
}

const int M = 250000;
int d[M+505], dp[M+505];
vi cnt(M+4);

int main()
{
    int n;
    cin >> n;

    vi a(n);
    int suma = 0;
    bool pp = 0, np = 0;
    for (auto& i : a){
        cin >> i;
        suma += i;

        if (i%2)
            np=1;
        else
            pp=1;
    }

    if ((pp && np) || suma%2) no();

    dp[0]=1;
    for (int i = 0; i < n; ++i){
        for (int j = M; j > -1; --j){
            dp[a[i]+j] += dp[j];
        }
    }

    if (!dp[suma/2]) no();

    vi sol;
    for (int i = 0; i < n; ++i){
        memset(d, 0, sizeof(d));

        for (int j = 0; j <= M; ++j){
            d[j] += dp[j];
            d[j+a[i]] -= d[j];
        }

        for (int j = 0; j <= M; ++j){
            if ((suma-a[i]+j)%2 == 0 && suma-a[i]-j>=0 && d[(suma-a[i]-j)/2]){
                ++cnt[j];
            }
        }
    }

    for (int i = 1; i <= M; ++i)
        if (cnt[i] == n)
            sol.push_back(i);

    cout << (int)sol.size() << '\n';

    for (auto& i : sol)
        cout << i << ' ';
}
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