Submission #340032

#TimeUsernameProblemLanguageResultExecution timeMemory
340032SprdaloMoney (IZhO17_money)C++17
45 / 100
1605 ms121252 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; typedef pair<int, int> pi; typedef pair<ll, ll> pl; typedef vector<int> vi; typedef vector<ll> vl; typedef vector<double> vd; typedef vector<bool> vb; typedef vector<char> vc; typedef vector<string> vs; typedef vector<pi> vp; typedef vector<pl> vpl; template<int MAXN> struct segtr{ //To change the purpose of the segtree just redefine the operators struct node{ int x; node(int x = 0) : x(x) {} node& operator+= (const node& other){ x += other.x; return *this; } node operator+ (const node& other){ node tmp = *this; return tmp += other; } }; node a[2*MAXN]; //Initialize the array void init(){ for(int i = 1; i <= MAXN; ++i){ a[i+MAXN-1] = node{}; } for(int i = MAXN-1; i > 0; --i){ a[i] = a[2*i] + a[2*i+1]; } } //Sets the node and updates the tree void set(int pos, node val){ pos += MAXN-1; a[pos] = val; while(pos > 1){ pos /= 2; a[pos] = a[2*pos] + a[2*pos+1]; } } inline void add(int pos, node val){ //Just forwards to set set(pos, node{a[pos+MAXN-1]+val}); } //Gets the range query node get(int l, int r, int pos = 1, int rl = 1, int rr = MAXN){ if(r < rl || rr < l){ return node{}; } if(l <= rl && rr <= r){ return a[pos]; } int rm = (rl+rr)/2; return get(l, r, 2*pos, rl, rm) + get(l, r, 2*pos+1, rm+1, rr); } }; segtr<131072*16> drvo; map<int, int> m; signed main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); cerr.tie(nullptr); int n; cin >> n; vi a(n); set<int> s; for (auto& i : a){ cin >> i; s.insert(i); } int cur = 1; for (auto& i : s){ m[i] = cur++; } for (auto& i : a){ i = m[i]; } drvo.init(); int l = 0, r = 1, sol = 1; while(1){ if (r == n) break; if (a[r] < a[r-1]){ for (int i = l; i < r; ++i) drvo.set(a[i], 1); ++sol; l = r; r++; drvo.set(a[l], 1); continue; } if (a[l]+1 > a[r]-1){ ++r; continue; } int x = drvo.get(a[l]+1, a[r]-1).x; if (!x){ ++r; continue; } for (int i = l; i < r; ++i) drvo.set(a[i], 1); l = r; ++sol; ++r; } cout<< sol << '\n'; }
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