Submission #339324

#	Time	Username	Problem	Language	Result	Execution time	Memory
339324		tengiz05	Riddick's Cube (IZhO13_riddicks)	C++17	100 / 100	1935 ms	492 KiB

riddicks

#include <bits/stdc++.h>
using namespace std;
#define int long long
#define FASTIO ios_base::sync_with_stdio(false); cin.tie(NULL);
#define all(x) (x).begin(), (x).end()
#define pb push_back
#define pii pair<int, int>
#define ff first
#define ss second
#define PI acos(-1)
#define ld long double
template<class T> bool ckmin(T& a, const T& b) {return a>b? a=b, true:false;}
template<class T> bool ckmax(T& a, const T& b) {return a<b? a=b, true:false;}
const int mod = 1e9+7, N = 4005;
int msb(int val){return sizeof(int)*8-__builtin_clzll(val)-1;}
int n, m, k;
int a[10][10];
int ans = 100500;
vector<int> opscol, opsrow;
int res[10][10];
int ops;
inline int shiftcol(int i, int j){
	int tt = min(j, n-j);
	for(int c=0;c<j;c++){
		res[n][i] = res[0][i];
		for(int I=0;I<n;I++){
			res[I][i] = res[I+1][i];
		}
	}return tt;
}

inline int shiftrow(int i, int j){
	int tt = min(j, m-j);
	for(int c=0;c<j;c++){
		res[i][m] = res[i][0];
		for(int I=0;I<m;I++){
			res[i][I] = res[i][I+1];
		}
	}return tt;
}

void row(int i){
	if(i == n){
		int tmp = 0;
		for(int j=0;j<n;j++){
			tmp += shiftrow(j, opsrow[j]);
		}ops += tmp;
		bool is1 = true, is2 = true;
		for(int i=0;i<n;i++){
			for(int j=1;j<m;j++)if(res[i][j] != res[i][j-1])is1 = false;
		}
		for(int i=0;i<m;i++){
			for(int j=1;j<n;j++)if(res[j][i] != res[j-1][i])is2 = false;
		}
		for(int j=0;j<n;j++){
			shiftrow(j, m-opsrow[j]);
		}
		if(is1 || is2)ckmin(ans, ops);
		ops -= tmp;
		return;
	}
	for(int j=0;j<m;j++){
		opsrow.pb(j);
		row(i+1);
		opsrow.pop_back();
	}
}

void col(int i){
	if(i == m){
		for(int c=0;c<n;c++)for(int r=0;r<m;r++)res[c][r] = a[c][r];
		int tmp = 0;
		for(int j=0;j<m;j++){
			tmp += shiftcol(j, opscol[j]);
		}
		ops += tmp;
		row(0);
		ops -= tmp;
		return;
	}
	for(int j=0;j<n;j++){
		opscol.pb(j);
		col(i+1);
		opscol.pop_back();
	}
}

void solve(int test_case){
	int i, j;
	cin >> n >> m;
	for(i=0;i<n;i++){
		for(j=0;j<m;j++){
			cin >> a[i][j];
		}
	}
	col(0);
	cout << ans << '\n';
	return;
}

signed main(){
	FASTIO;
#define MULTITEST 0
#if MULTITEST
	int _T;
	cin >> _T;
	for(int T_CASE = 1; T_CASE <= _T; T_CASE++)
		solve(T_CASE);
#else
	solve(1);
#endif
	return 0;
}

• Subtask 1: 100 / 100