제출 #338482

#제출 시각아이디문제언어결과실행 시간메모리
338482Dilshod_ImomovEvacuation plan (IZhO18_plan)C++17
0 / 100
302 ms61164 KiB
# include <bits/stdc++.h>
# define speed ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0)
# define int long long
# define fi first
# define se second
 
using namespace std;
 
const int N = 2e6 + 7;
const int mod = 1e9 + 7;

vector < pair < int, int > > adj[N];
int dist[N];

int32_t main() {
    speed;
    int n, m;
    cin >> n >> m;
    for ( int i = 1; i <= m; i++ ) {
        int u, v, w;
        cin >> u >> v >> w;
        adj[u].push_back( { v, w } );
        adj[v].push_back( { u, w } );
    }
    for ( int i = 1; i <= n; i++ ) {
        dist[i] = 1e9;
    }
    int k;
    cin >> k;
    set < pair < int, int > > q;
    for ( int i = 1; i <= k; i++ ) {
        int x;
        cin >> x;
        q.insert( { 0, x } );
        dist[x] = 0;
    }
    while ( !q.empty() ) {
        int v = q.begin()->se;
        q.erase( q.begin() );
        for ( auto pr: adj[v] ) {
            int u = pr.fi, w = pr.se;
            if ( dist[u] > dist[v] + w ) {
                q.erase( { dist[u], u } );
                dist[u] = dist[v] + w;
                q.insert( { dist[u], u } );
            }
        }
    }
    int qr;
    cin >> qr;
    while ( qr-- ) {
        int a, b;
        cin >> a >> b;
        cout << max( dist[a], dist[b] ) << '\n';
    }
}
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