Submission #33694

#	Time	Username	Problem	Language	Result	Execution time	Memory
33694		imaxblue	Potemkin cycle (CEOI15_indcyc)	C++14	20 / 100	49 ms	5552 KiB

indcyc

#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define mp make_pair
#define pb push_back
#define x first
#define y second
#define pii pair<int, int>
#define p3i pair<pii, int>
#define pll pair<ll, ll>
#define p3l pair<pll, ll>
#define lseg L, (L+R)/2, N*2+1
#define rseg (L+R)/2+1, R, N*2+2
#define ub upper_bound
#define lb lower_bound
#define pq priority_queue
#define MN 1000000007
#define fox(k, x) for (int k=0; k<x; ++k)
#define fox1(k, x) for (int k=1; k<=x; ++k)
#define foxr(k, x) for (int k=x-1; k>=0; --k)
#define fox1r(k, x) for (int k=x; k>0; --k)
#define ms multiset
#define flood(x) memset(x, 0x3f3f3f3f, sizeof x)
#define drain(x) memset(x, 0, sizeof x)
#define rng() (rand() >> 3)*rand()

int n, m, a, b, com[1005], pre[1005], p, N, P;
bool u[1005], u2[1005], adj[1005][1005];
vector<int> v[1005], s;
void dfs(int N){
    if (u2[N]) return;
    u2[N]=1;
    if (u[N]){
        s.pb(N);
        return;
    }
    fox(l, v[N].size()) dfs(v[N][l]);
}
queue<pii> q;
void bfs(int S, int T,int L){
    q.push(mp(S, -1));
    memset(u2, 0, sizeof u2);
    u2[L]=1;
    while(!q.empty()){
        N=q.front().x; P=q.front().y; q.pop();
        if (u2[N]) continue;
        u2[N]=1; pre[N]=P;
        if (N==T) break;
        fox(l, v[N].size()){
            q.push(mp(v[N][l], N));
        }
    }
    while(T!=S){
        cout << T << ' ';
        T=pre[T];
    }
    cout << S << ' ' << L << endl;
}
int main(){
    cin >> n >> m;
    fox(l, m){
        cin >> a >> b;
        v[a].pb(b);
        v[b].pb(a);
        adj[a][b]=adj[b][a]=1;
    }
    fox1(l, n){
        fox1(l2, n){
            u[l2]=adj[l][l2];
        }
        u[l]=1;
        memset(u2, 0, sizeof u2);
        u2[l]=1;
        fox1(l2, n){
            if (u[l2] || u2[l2]) continue;
            s.clear();
            dfs(l2);
            fox(l3, s.size()){
                for(int l4=l3+1; l4<s.size(); ++l4){
                    if (!adj[s[l3]][s[l4]]){
                        bfs(s[l3], s[l4], l);
                        return 0;
                    }
                }
            }
        }
        fox(l2, v[l].size()){
            for(int l3=l2+1; l3<v[l].size(); ++l3){
                if (!adj[l2][l3] && com[l2]==com[l3]){

                }
            }
        }
    }
    cout << "no";
    return 0;
}

Compilation message (stderr)

indcyc.cpp: In function 'void dfs(int)':
indcyc.cpp:18:34: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
 #define fox(k, x) for (int k=0; k<x; ++k)
                                  ^
indcyc.cpp:37:5: note: in expansion of macro 'fox'
     fox(l, v[N].size()) dfs(v[N][l]);
     ^
indcyc.cpp: In function 'void bfs(int, int, int)':
indcyc.cpp:18:34: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
 #define fox(k, x) for (int k=0; k<x; ++k)
                                  ^
indcyc.cpp:49:9: note: in expansion of macro 'fox'
         fox(l, v[N].size()){
         ^
indcyc.cpp: In function 'int main()':
indcyc.cpp:18:34: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
 #define fox(k, x) for (int k=0; k<x; ++k)
                                  ^
indcyc.cpp:78:13: note: in expansion of macro 'fox'
             fox(l3, s.size()){
             ^
indcyc.cpp:79:36: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
                 for(int l4=l3+1; l4<s.size(); ++l4){
                                    ^
indcyc.cpp:18:34: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
 #define fox(k, x) for (int k=0; k<x; ++k)
                                  ^
indcyc.cpp:87:9: note: in expansion of macro 'fox'
         fox(l2, v[l].size()){
         ^
indcyc.cpp:88:32: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
             for(int l3=l2+1; l3<v[l].size(); ++l3){
                                ^

• Subtask 1: 10 / 10
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10
• Subtask 4: 10 / 10
• Subtask 5: 0 / 10
• Subtask 6: 0 / 10
• Subtask 7: 0 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 10
• Subtask 10: 0 / 10