This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <array>
#include <unordered_map>
using namespace std;
#define endl '\n'
#define ll long long
#define pi pair<int, int>
#define f first
#define s second
typedef array<int, 2> T;
T operator+(T x, T y){
return {x[0] + y[0], x[1] + y[1]};
}
const int mxn = 50000, k = 4;
const T d[k] = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};
int n[2], q;
int a[2][mxn];
unordered_map<int, int> dp[k][mxn];
bool f(T x){
for(int i = 0; i < 2; i++) if(x[i] < 0 || x[i] >= n[i]) return 0;
return 1;
}
int sol(T x, int y){
int ret = 0, s = 0;
for(; f(x) && a[!(y & 1)][x[!(y & 1)]] > a[y & 1][x[y & 1]]; x = x + d[y]) s++;
if(!f(x)) return s;
if(dp[y][x[0]].count(x[1])) return dp[y][x[0]][x[1]] + s;
for(int i = 0; i < 2; i++){
int z = (y + 2 * i + 1) % k;
ret = max(ret, sol(x + d[z], z));
}
dp[y][x[0]][x[1]] = ++ret;
return ret + s;
}
int main(){
ios::sync_with_stdio(0);
cin.tie(0);
cin >> n[0] >> n[1] >> q;
if(max(n[0], n[1]) == mxn) return 0;
for(int i = 0; i < 2; i++)
for(int j = 0; j < n[i]; j++){
cin >> a[i][j];
}
while(q--){
T x;
for(int i = 0; i < 2; i++) cin >> x[i], x[i]--;
int ret = 0;
for(int i = 0; i < k; i++) ret = max(ret, sol(x + d[i], i));
cout << ret << endl;
}
return 0;
}
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