Submission #336756

#	Time	Username	Problem	Language	Result	Execution time	Memory
336756		super_j6	Abduction 2 (JOI17_abduction2)	C++14	13 / 100	5044 ms	84832 KiB

abduction2

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <array>
using namespace std;
#define endl '\n'
#define ll long long
#define pi pair<int, int>
#define f first
#define s second

typedef array<int, 2> T;

T operator+(T x, T y){
	return {x[0] + y[0], x[1] + y[1]};
}

const int mxn = 50000, k = 4;
const T d[k] = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};
int n[2], q;
int a[2][mxn];

int sol(T x, int y){
	for(int i = 0; i < 2; i++) if(x[i] < 0 || x[i] >= n[i]) return 0;
	int ret = 0;
	if(a[!(y & 1)][x[!(y & 1)]] < a[y & 1][x[y & 1]]){
		for(int i = 0; i < 2; i++){
			int z = (y + 2 * i + 1) % k;
			ret = max(ret, sol(x + d[z], z));
		}
	}else{
		ret = sol(x + d[y], y);
	}
	return ++ret;
}

int main(){
	ios::sync_with_stdio(0);
	cin.tie(0);
	
	cin >> n[0] >> n[1] >> q;
	
	for(int i = 0; i < 2; i++)
	for(int j = 0; j < n[i]; j++){
		cin >> a[i][j];
	}
	
	while(q--){
		T x;
		for(int i = 0; i < 2; i++) cin >> x[i], x[i]--;
		int ret = 0;
		for(int i = 0; i < k; i++) ret = max(ret, sol(x + d[i], i));
		cout << ret << endl;
	}

	return 0;
}

• Subtask 1: 13 / 13
• Subtask 2: 0 / 10
• Subtask 3: 0 / 17
• Subtask 4: 0 / 4
• Subtask 5: 0 / 56