This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<bits/stdc++.h>
#pragma GCC optimize("unroll-loops,no-stack-protector")
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<ll,ll> pll;
const ll MOD=1e9+7;
const ll MOD2=998244353;
const ll N=2e5+5;
const ld pi=3.14159265359;
const ll INF=(1LL<<60);
#define SQ(i) ((i)*(i))
#define REP(i,n) for(ll i=0;i<n;i++)
#define REP1(i,n) for(ll i=1;i<=n;i++)
#define pb push_back
#define mp make_pair
#define X first
#define Y second
#define setp setprecision
#define lwb lower_bound
#define SZ(_a) (ll)_a.size()
ll n,x,wa,wb,y,ans[N],down[N],fr[N],fn[N],dsum,q,sub[N][2],vis[N],rta,rtb;
vector<pair<ll,pll> > v[N];
priority_queue<ll> pq;
void PDFS(ll nd,ll Parent){
sub[nd][0]=sub[nd][1]=down[nd]=nd;
for(auto i:v[nd]){
if(i.X==Parent)continue;
fn[i.X]=fn[nd]+i.Y.Y;
fr[i.X]=fr[nd]+i.Y.X;
dsum+=i.Y.X;
PDFS(i.X,nd);
down[nd]=(fr[down[i.X]]>fr[down[nd]]?down[i.X]:down[nd]);
ll id=down[i.X];
if(fr[sub[nd][0]]<=fr[id])swap(id,sub[nd][0]);
if(fr[sub[nd][1]]<=fr[id])swap(id,sub[nd][1]);
}
}
ll DFS(ll nd,ll pa){
vis[nd]=(nd==rtb?1:0);
for(auto i:v[nd]){
if(i.X==pa)continue;
vis[i.X]=DFS(i.X,nd);
vis[nd]|=vis[i.X];
if(vis[i.X])continue;
dsum+=i.Y.X;
fr[i.X]+=i.Y.X;
fr[nd]=max(fr[nd],fr[i.X]);
}
ll cnt=0;
for(auto i:v[nd]){
if(i.X==pa||vis[i.X])continue;
if(cnt==0&&fr[nd]==fr[i.X]){
++cnt;
}else{
pq.push(fr[i.X]);
}
}
return vis[nd];
}
int main(){
ios_base::sync_with_stdio(0);cin.tie(0);
cin>>n;
REP(i,n-1){
cin>>x>>y>>wa>>wb;
v[x].pb(mp(y,mp(wa,wb)));
v[y].pb(mp(x,mp(wb,wa)));
}
PDFS(1,0);
REP1(i,n)ans[i]=INF;
REP1(i,n){
ans[1]=min(ans[1],dsum+fn[i]-fr[i]);
if(dsum+fn[i]+fr[i]-(fr[sub[i][0]]+fr[sub[i][1]])<ans[2]){
rta=sub[i][0];rtb=sub[i][1];
ans[2]=dsum+fn[i]+fr[i]-(fr[sub[i][0]]+fr[sub[i][1]]);
}
}
memset(fn,0,sizeof(fn));
memset(fr,0,sizeof(fr));
dsum=0;
DFS(rta,0);
REP1(i,n)if(vis[i])pq.push(fr[i]);
for(int i=3;i<=n;i++){
if(SZ(pq)==0){ans[i]=ans[i-1];continue;}
ans[i]=ans[i-1]-pq.top()+dsum;
pq.pop();
}
cin>>q;
while(q--){
cin>>x;
cout<<ans[x]<<"\n";
}
return 0;
}
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