Submission #333659

#TimeUsernameProblemLanguageResultExecution timeMemory
333659apostoldaniel854Hyper-minimum (IZhO11_hyper)C++14
100 / 100
515 ms44396 KiB
#include <bits/stdc++.h> using namespace std; using ll = long long; #define pb push_back #define dbg(x) cerr << #x << " " << x << "\n" struct MinDeque { deque <pair <int, int>> dq; inline void add (int val, int index) { while (dq.size () && dq.back ().first >= val) dq.pop_back (); dq.push_back ({val, index}); } inline int extract (int bound) { while (dq.size () && dq.front ().second < bound) dq.pop_front (); return dq.front ().first; } }; int main () { ios::sync_with_stdio (false); cin.tie (0); cout.tie (0); int n, m; cin >> n >> m; vector <vector <vector <vector <int>>>> X, Y; X.resize (n + 1); for (int i = 1; i <= n; i++) { X[i].resize (n + 1); for (int j = 1; j <= n; j++) { X[i][j].resize (n + 1); for (int k = 1; k <= n; k++) { X[i][j][k].resize (n + 1); for (int l = 1; l <= n; l++) { cin >> X[i][j][k][l]; } } } } Y = X; for (int i = 1; i <= n; i++) for (int j = 1; j <= n; j++) for (int k = 1; k <= n; k++) { MinDeque dq; for (int l = 1; l <= n; l++) { dq.add (Y[i][j][k][l], l); if (l >= m) Y[i][j][k][l - m + 1] = dq.extract (l - m + 1); } } for (int i = 1; i <= n; i++) for (int j = 1; j <= n; j++) for (int l = 1; l <= n - m + 1; l++) { MinDeque dq; for (int k = 1; k <= n; k++) { dq.add (Y[i][j][k][l], k); if (k >= m) Y[i][j][k - m + 1][l] = dq.extract (k - m + 1); } } for (int i = 1; i <= n; i++) for (int k = 1; k <= n - m + 1; k++) for (int l = 1; l <= n - m + 1; l++) { MinDeque dq; for (int j = 1; j <= n; j++) { dq.add (Y[i][j][k][l], j); if (j >= m) Y[i][j - m + 1][k][l] = dq.extract (j - m + 1); } } for (int j = 1; j <= n - m + 1; j++) for (int k = 1; k <= n - m + 1; k++) for (int l = 1; l <= n - m + 1; l++) { MinDeque dq; for (int i = 1; i <= n; i++) { dq.add (Y[i][j][k][l], i); if (i >= m) Y[i - m + 1][j][k][l] = dq.extract (i - m + 1); } } for (int i = 1; i <= n - m + 1; i++) for (int j = 1; j <= n - m + 1; j++) for (int k = 1; k <= n - m + 1; k++) for (int l = 1; l <= n - m + 1; l++) cout << Y[i][j][k][l] << " "; cout << "\n"; return 0; }
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