# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
333532 | doowey | NLO (COCI18_nlo) | C++14 | 3075 ms | 8172 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
#define fi first
#define se second
#define mp make_pair
#define fastIO ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
const int N = (int)1e5 + 100;
const int K = 105;
int x[K], y[K], r[K];
int xl[K], xr[K];
vector<int> add[N];
vector<int> rem[N];
ll sq(ll x){
return x * 1ll * x;
}
struct Node{
int cnt;
int lazy;
};
Node T[N * 4 + 512];
void push(int node, int cl, int cr){
if(T[node].lazy == -1) return;
if(T[node].lazy == 0)
T[node].cnt=0;
else
T[node].cnt=(cr-cl+1);
if(cl != cr){
T[node<<1].lazy=T[node].lazy;
T[node<<1|1].lazy=T[node].lazy;
}
T[node].lazy = -1;
}
int get(int node, int cl, int cr, int tl, int tr){
push(node,cl,cr);
if(cr < tl || cl > tr) return 0;
if(cl >= tl && cr <= tr){
return T[node].cnt;
}
int mid = (cl + cr) / 2;
return get(node<<1,cl,mid,tl,tr)+get(node<<1|1,mid+1,cr,tl,tr);
}
void update(int node, int cl, int cr, int tl, int tr, int type){
push(node, cl, cr);
if(cr < tl || cl > tr) return;
if(cl >= tl && cr <= tr){
T[node].lazy=type;
push(node,cl,cr);
return;
}
int mid = (cl + cr) / 2;
update(node<<1,cl,mid,tl,tr,type);
update(node<<1|1,mid+1,cr,tl,tr,type);
T[node].cnt = T[node<<1].cnt + T[node<<1|1].cnt;
}
int main(){
fastIO;
int n, m, k;
cin >> n >> m >> k;
for(int i = 1; i <= k ; i ++ ){
cin >> x[i] >> y[i] >> r[i];
add[x[i]-r[i]].push_back(i);
xl[i]=xr[i]=y[i];
rem[x[i]+r[i]+1].push_back(i);
}
for(int i = 1; i <= m * 4 + 100; i ++ ){
T[i] = {0,-1};
}
set<int> active;
ll soln = 0;
int id;
for(int i = 1; i <= n; i ++ ){
for(auto xx : add[i]){
active.insert(xx);
}
for(auto xx : rem[i]){
active.erase(xx);
}
for(auto xx : active){
if(i <= x[xx]){
while(sq((xl[xx]-1)-y[xx]) + sq(i-x[xx]) <= sq(r[xx])){
xl[xx]--;
xr[xx]++;
}
}
else{
while(sq(xl[xx]-y[xx])+sq(i-x[xx]) > sq(r[xx])){
xl[xx]++;
xr[xx]--;
}
}
}
auto it = active.end();
update(1, 1, m, 1, m, 1);
while(it != active.begin()){
it -- ;
id = *it;
soln += (k-id) * 1ll * get(1, 1, m, xl[id], xr[id]);
update(1, 1, m, xl[id], xr[id], 0);
}
soln += k * 1ll * T[1].cnt;
}
cout << soln << "\n";
return 0;
}
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---|---|---|---|---|
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