Submission #331038

#TimeUsernameProblemLanguageResultExecution timeMemory
331038caoashMostovi (COI14_mostovi)C++17
0 / 100
275 ms15084 KiB
/* * Consider some path from u to v. * * Define the range of some guy u as [u, first before u that has edge cut]. * * Define the range of v similarly. * * Then if there exists a bridge between [l1, r1] and [l2, r2], then u can reach v. * * Try to view it as points. * * Problem reduces to: add a point, check if rectangle contains point. * Another constraint: points are always monotoncially increasing * - binary search for first point with x >= left edge of rect and y >= bottom edge of rect * - check if x <= right edge of rect and y <= top edge of rect */ #include <bits/stdc++.h> using namespace std; using ll = long long; using vi = vector<int>; using vl = vector<ll>; #define pb push_back #define all(x) begin(x), end(x) #define sz(x) (int)(x).size() #define lb lower_bound #define ub upper_bound using pi = pair<int,int>; #define f first #define s second #define mp make_pair const int MX = 200005; const int MOD = (int) (1e9 + 7); const ll INF = (ll) 1e18; namespace output { void pr(int x) { cout << x; } void pr(long x) { cout << x; } void pr(ll x) { cout << x; } void pr(unsigned x) { cout << x; } void pr(unsigned long x) { cout << x; } void pr(unsigned long long x) { cout << x; } void pr(float x) { cout << x; } void pr(double x) { cout << x; } void pr(long double x) { cout << x; } void pr(char x) { cout << x; } void pr(const char * x) { cout << x; } void pr(const string & x) { cout << x; } void pr(bool x) { pr(x ? "true" : "false"); } template < class T1, class T2 > void pr(const pair < T1, T2 > & x); template < class T > void pr(const T & x); template < class T, class...Ts > void pr(const T & t, const Ts & ...ts) { pr(t); pr(ts...); } template < class T1, class T2 > void pr(const pair < T1, T2 > & x) { pr("{", x.f, ", ", x.s, "}"); } template < class T > void pr(const T & x) { pr("{"); // const iterator needed for vector<bool> bool fst = 1; for (const auto & a: x) pr(!fst ? ", " : "", a), fst = 0; pr("}"); } void ps() { pr("\n"); } // print w/ spaces template < class T, class...Ts > void ps(const T & t, const Ts & ...ts) { pr(t); if (sizeof...(ts)) pr(" "); ps(ts...); } void pc() { cout << "]" << endl; } // debug w/ commas template < class T, class...Ts > void pc(const T & t, const Ts & ...ts) { pr(t); if (sizeof...(ts)) pr(", "); pc(ts...); } //#define dbg(x...) pr("[", #x, "] = ["), pc(x); } #ifdef mikey using namespace output; #else using namespace output; //#define dbg(x...) #endif #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> using namespace __gnu_pbds; template <class T> using PeanutButter = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; #define ook order_of_key #define fbo find_by_order PeanutButter<pi> pts; set<int> bad[2]; set<int> pre[2]; int main(){ #ifdef mikey freopen("a.in", "r", stdin); #endif ios::sync_with_stdio(false); cin.tie(0); int n, m; cin >> n >> m; bad[0].insert(n), bad[1].insert(n); pre[0].insert(1), pre[1].insert(1); auto has = [&] (pi xs, pi ys) { int ans = -1; int lo = 0, hi = sz(pts) - 1; //dbg(pts); while (lo <= hi) { int mid = (lo + hi) / 2; pi cur = *pts.fbo(mid); //dbg(mid, cur); if (cur.f >= xs.f && cur.s >= ys.f) { hi = mid - 1; ans = mid; } else { lo = mid + 1; } } if (ans == -1) return false; else { pi cur = *pts.fbo(ans); //dbg(cur); if (cur.f <= xs.s && cur.s <= ys.s) { return true; } return false; } }; for (int i = 0; i < m; i++) { char qt; cin >> qt; if (qt == 'A') { int x, y; cin >> x >> y; if (x > y) swap(x, y); if (y > n) y -= n; pts.insert(mp(x, y)); } else if (qt == 'B') { int x, y; cin >> x >> y; //dbg("REM", x, y); bool c = (x > n); x -= (n * c); y -= (n * c); bad[c].insert(min(x, y)); pre[c].insert(max(x, y)); } else { int x, y; cin >> x >> y; int c = (x > n), c2 = (y > n); x -= (n * c); y -= (n * c2); //dbg("QUERY", x, y); if (c == c2) { int go = *(bad[c].lb(min(x, y))); if (go >= y) cout << "DA\n"; else cout << "NE\n"; } else { pi r1 = mp(x, *bad[c].lb(x)); pi r2 = mp(y, *bad[c2].lb(y)); if (c) { r1 = mp(*(--pre[c].ub(x)), x); r2 = mp(*(--pre[c2].ub(y)), y); } //dbg(r1, r2); if (has(r1, r2)) cout << "DA\n"; else cout << "NE\n"; } } } }
#Verdict Execution timeMemoryGrader output
Fetching results...