이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")
#include <iostream>
#include <fstream>
#include <algorithm>
#include <vector>
#include <set>
#include <stack>
#include <map>
#include <unordered_map>
#include <iomanip>
#include <cmath>
#include <queue>
#include <bitset>
#include <numeric>
#include <array>
#include <cstring>
#include <random>
#include <chrono>
#define fi first
#define se second
#define pb push_back
#define mp make_pair
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define make_unique(x) sort(all((x))); (x).resize(unique(all((x))) - (x).begin())
typedef long long ll;
typedef long double ld;
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/tree_policy.hpp>
// using namespace __gnu_pbds;
// template<class T>
// using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
int main() {
ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
ld k, d, t;
cin >> k >> d >> t;
ld l = t, r = 2 * t;
ld onec = ((ll)k + (ll)d - 1) / (ll)d * d;
ld get = k * 2 + (onec - k);
for(int it = 0; it < 250; it++) {
ld mid = (l + r) / 2.;
ld curget = (ll)mid / (ll)onec * get;
ld left = mid - ((ll)mid / (ll)onec) * onec;
if(left <= k) curget += left * 2.;
else {
curget += k * 2.;
curget += (left - k);
}
if(curget >= t * 2.) r = mid;
else l = mid;
}
cout << fixed << setprecision(10) << l;
return 0;
}
/*
*/
컴파일 시 표준 에러 (stderr) 메시지
B.cpp:3: warning: ignoring #pragma GCC optimization [-Wunknown-pragmas]
3 | #pragma GCC optimization ("unroll-loops")
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