Submission #330751

#TimeUsernameProblemLanguageResultExecution timeMemory
330751IgorIAliens (IOI16_aliens)C++17
41 / 100
2086 ms5740 KiB
#include <bits/stdc++.h> using namespace std; const long long INFLL = 1e18; pair<long long, long long> calc(int n, long long M, vector<int> l, vector<int> r) { vector<long long> dp(n, INFLL); vector<long long> bl(n, INFLL); for (int i = 0; i < n; i++) dp[i] = M + 1ll * (r[i] - l[0] + 1) * (r[i] - l[0] + 1), bl[i] = 1; struct line{ long long k, b, id; }; vector<line> convex; for (int i = 0; i < n; i++) { long long res = 1ll * r[i] * r[i]; long long d = INFLL, used = 0; for (auto e : convex) { if (e.b + e.k * r[i] < d) d = e.b + e.k * r[i], used = INFLL; if (e.b + e.k * r[i] == d && bl[e.id] < used) used = bl[e.id]; } res += d; if (res < dp[i]) dp[i] = res, bl[i] = used + 1; if (i + 1 < n) { long long b = dp[i] + 1ll * l[i + 1] * l[i + 1] + 1 - 2 * l[i + 1] + M - 1ll * max(0, r[i] - l[i + 1] + 1) * max(0, r[i] - l[i + 1] + 1); long long k = 2 * (1 - l[i + 1]); line L = {k, b, i}; while (convex.size() >= 2) { line A = convex[convex.size() - 2]; line B = convex[convex.size() - 1]; if (1ll * (B.b - L.b) * (L.k - B.k) > 1ll * (A.b - L.b) * (L.k - B.k)) convex.pop_back(); else break; } convex.push_back(L); } } //cout << M << " " << dp[n - 1] << " " << bl[n - 1] << endl; return {dp[n - 1], bl[n - 1]}; } long long take_photos(int n, int m, int k, vector<int> l, vector<int> r) { vector<int> cv(m); for (int i = 0; i < m; i++) { cv[i] = i + 1; } for (int i = 0; i < n; i++) { int x = min(l[i], r[i]); int y = max(l[i], r[i]); cv[y] = min(cv[y], x); } l.clear(); r.clear(); for (int i = 0; i < m; i++) { if (cv[i] <= i) { while (l.size() && l.back() >= cv[i]) l.pop_back(), r.pop_back(); l.push_back(cv[i]), r.push_back(i); } } n = l.size(); //for (int i = 0; i < l.size(); i++) // cout << l[i] << " " << r[i] << endl; long long L = 0, R = 1ll * m * m + 222; long long ans = INFLL; k = min(k, n); while (L + 1 < R) { long long M = (L + R) / 2; if (calc(n, M, l, r).second >= k) L = M; else R = M; } for (long long d = R - 1; d <= R; d++) { pair<long long, long long> res = calc(n, d, l, r); //cout << res.first << " " << res.second << " " << d << " " << k << endl; if (res.second <= k) ans = min(ans, res.first - 1ll * k * d); } return ans; }
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