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Submission #330118

#TimeUsernameProblemLanguageResultExecution timeMemory
330118ignaciocantaTraffic (IOI10_traffic)C++14
100 / 100
1163 ms170860 KiB
#include <bits/stdc++.h> #include <traffic.h> using namespace std; using tint = long long; using ld = long double; #define forsn(i, s, n) for(int i = s; i < int(n); i++) #define forn(i, n) forsn(i, 0, n) #define trav(a, x) for(auto& a : x) using vi = vector<int>; using vl = vector<tint>; using vb = vector<bool>; #define pb push_back #define pf push_front #define rsz resize #define all(x) begin(x), end(x) #define rall(x) x.rbegin(), x.rend() #define sz(x) (int)(x).size() #define ins insert #define esta(x,c) ((c).find(x) != (c).end()) using pi = pair<int,int>; using pl = pair<tint,tint>; #define f first #define s second #define mp make_pair #define DBG(x) cerr << #x << " = " << x << endl; const int MOD = 1e9+7; const tint mod = 998244353; const int MX = 1e6+5; const tint INF = 1e18; const int inf = 2e9; const ld PI = acos(ld(-1)); const ld eps = 1e-8; const int dx[4] = {1, -1, 0, 0}; const int dy[4] = {0, 0, 1, -1}; template<class T> void remDup(vector<T> &v){ sort(all(v)); v.erase(unique(all(v)),end(v)); } template<class T> bool valid(T x, T y, T n, T m){ return (0<=x && x<n && 0<=y && y<m); } int cdiv(int a, int b) { return a/b+((a^b)>0&&a%b); } //redondea p arriba int fdiv(int a, int b) { return a/b-((a^b)<0&&a%b); } //redonde p abajo void NACHO(string name = "cbarn"){ ios_base::sync_with_stdio(0); cin.tie(0); //freopen((name+".in").c_str(), "r", stdin); //freopen((name+".out").c_str(), "w", stdout); } vi adj[MX]; int dp[MX]; int val[MX]; int sum = 0; int best = inf; int ret; void dfs(int node, int pa){ int sumSon = 0; int maxi = 0; trav(u, adj[node]){ if(u != pa){ sumSon+=val[u]; dfs(u, node); maxi = max(maxi, val[u]+dp[u]); sumSon+=dp[u]; dp[node]+=val[u]+dp[u]; } } int dad = sum-sumSon-val[node]; maxi = max(maxi, dad); if(maxi < best){ best = maxi; ret = node; } } int LocateCentre(int n, int p[], int d[], int s[]){ forn(i, n) val[i] = p[i], sum+=val[i]; forn(i, n-1){ adj[d[i]].pb(s[i]); adj[s[i]].pb(d[i]); } dfs(0, -1); return ret; }
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